java - 如何在ArrayLists中使用多态？

所以我有这个动物园程序，我想要一个动物园中的房间列表，以及每个房间中的猫列表。

我有3个类：Felid，Housecat和Wildcat-Housecat和Wildcat扩展Felid。根据动物的字面类别（现在我有老虎，波斯，暹罗和猎豹-老虎和猎豹扩展了野猫，波斯和暹罗扩展了家猫），某些属性将自动分配。

类图-http://i.imgur.com/VTSNRVA.jpg

例如，这些是felid的字段：

String speciesName;
String furColour;
String gender;
int weightPounds;
boolean packAnimal;
String habitat;
int age;

这些是家猫的字段：

String ownerName;
String catName;
boolean feral;

这些是野猫的字段：

boolean manEater;

在我的家猫构造函数中，我有

    if(catName == null || catName.equals("")){
        feral = true;
    }

如果是猫的野性，则当用户使用猫的名称创建HouseCat并使用“ printCatInfo（）”时：

@Override
public void printCatInfo(){
    if(feral){
        System.out.println("feral" + "\n" + speciesName + "\n" + furColour + "\n" + gender +
            "\n" + weightPounds + "lbs\n" + "is not a pack animal" + "\n" + habitat + "\n" + age + " years old (human)");
    }
    else{
        System.out.println("owner name is: " + ownerName + "\n" + "cat name is: " + catName + "\n" + speciesName + "\n" + furColour + "\n" + gender +
            "\n" + weightPounds + "lbs\n" + "is not a pack animal" + "\n" + habitat + "\n" + age + " years old (human)" + "\n");
    }
}

它不会打印其名称。

feral
siamese
White or grey abdomen with black legs, face and tail
male
8lbs
is not a pack animal
urban
7 years old (human)

麻烦的是，我认为所有猫都属于野猫，因为我用于猫列表的列表是：

ArrayList<Felid> catList = new ArrayList<Felid>();

因此，我猜catName始终为null，因为添加到列表中的家猫只会算作“猫科动物”类型。

如何创建一个列表，我可以将所有的猫都扔进去，但仍然将它们视为各自的类？

编辑：感谢指出赋值运算符错误，虽然它仍然只打印野性

最终编辑：非常感谢'DoubleDouble'向我指出如何使用'Super（）'-这不是我期望的问题。这是问题所在：

public class Siamese extends HouseCat{
    public Siamese(int weightPounds, int age, String ownerName, String catName, String gender){
        this.speciesName = "siamese";
        this.furColour = "White or grey abdomen with black legs, face and tail";
        this.ownerName = ownerName;
        this.catName = catName;
        this.weightPounds = weightPounds;
        this.age = age;
        this.gender = gender;
    }
}

新代码：

public class Siamese extends HouseCat{
    public Siamese(int weightPounds, int age, String ownerName, String catName, String gender){
        super(catName);
        this.speciesName = "siamese";
        this.furColour = "White or grey abdomen with black legs, face and tail";
        this.ownerName = ownerName;
        this.catName = catName;
        this.weightPounds = weightPounds;
        this.age = age;
        this.gender = gender;
    }
}

最佳答案

您的构造函数似乎如下（如果我做错了，请纠正我）：

public Siamese(int weightPounds, int age, String ownerName, String catName, String gender)
{
    this.weightPounds = weightPounds;
    this.age = age;
    this.ownerName = ownerName;
    this.catName = catName;
    this.gender = gender;
}

public HouseCat()
{
    if(catName == null || catName.equals(""))
    {
        feral = true;
    }
}

由于ownerName，catName和feral都是HouseCat类的一部分，因此最好让HouseCat构造函数处理这些字段。

public HouseCat(String ownerName, String catName)
{
    this.ownerName = ownerName;
    this.catName = catName;
    if(catName == null || catName.equals(""))
    {
        feral = true;
    }
}

连体语言如下：

public Siamese(int weightPounds, int age, String ownerName, String catName, String gender)
{
    super(ownerName, catName);
    this.weightPounds = weightPounds;
    this.age = age;
    this.gender = gender;
}