如果我有以下收藏:

{
    "restaurant": {
        "_id": "5c0711f23533ef13a3e53d8b",
        "name": "burger king",
        "description": "american",
        "reservations": [
            {
                "_id": "5c0712503533ef13a3e53d8c",
                "time": "1:00 pm",
                "people": 3
            },
            {
                "_id": "5c0717129a8d7213e46d92da",
                "time": "9:30 am",
                "people": 10
            },
            {
                "_id": "5c071960160f2a13f647e100",
                "time": "12:30 am",
                "people": 25
            }
        ],
        "__v": 0
    }
}


如果我要发布,则仅返回带有餐厅的_id,名称,描述的特定预订,例如:

{
    "restaurant": {
        "_id": "5c0711f23533ef13a3e53d8b",
        "name": "burger king",
        "description": "american",
        "reservations": [
            {
                "_id": "5c0717129a8d7213e46d92da",
                "time": "9:30 am",
                "people": 10
            }
        ],
        "__v": 0
    }
}


最好的方法是什么?

我试过了:

Restaurant.find( {_id: ObjectID(id)}, {reservations : { $elemMatch: {time: time} }, {$elemMatch: {people: people}} } )
.then( (restaurant)=> {
    res.send({restaurant})
})


但不起作用。
任何帮助,将不胜感激

最佳答案

您的查询不正确。

匹配应如下所示:

Restaurant.find( {_id: ObjectID(id)}, {
   name: 1,
   description: 1,
   reservations : { $elemMatch: {time: time, people: people} } } )
.then( (restaurant)=> {
    res.send({restaurant})
})


并确保_id实际上是ObjectID类型而不是String类型

以下查询工作正常(在本地测试):

db.getCollection('test').find({_id: '5c0711f23533ef13a3e53d8b'}, {name:1, description: 1, reservations: {$elemMatch: {people: 3, time: '1:00 pm'}}})


请注意,我使用的是字符串_id而不是对象ID。

关于javascript - MongoDB:如何在JSON中返回特定字段和特定子文档,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/53623586/

10-16 19:41