python - Django Models.py数据库设计反馈

根据我收到的previous question和反馈，我重新设计了模型，并在运行“ syncdb”之前需要一些反馈。

我主要关心的是ForeignKeys和Restaurant表中的一个ManyToManyField。 ManyTomany字段也应该具有through =''值，该值应该是什么？

任何反馈表示赞赏！

楷模

class Restaurant(models.Model):
    id = models.AutoField(primary_key=True, db_column='id')
    name = models.CharField(max_length=50L, db_column='name', blank=True)
    address = models.CharField(max_length=100L, blank=True)
    city_id = models.ForeignKey('City', related_name="restaurant_city")
    location_id = models.ForeignKey('Location', related_name="restaurant_location")
    hood_id = models.ForeignKey('Hood', null=True, blank=True, related_name="restaurant_hood")
    listingrole_id = models.ForeignKey('Listingrole', related_name="restaurant_listingrole")
    cuisine_types = models.ManyToManyField('Cuisinetype', null=True, blank=True, related_name="restaurant_cuisinetype")
    class Meta:
        db_table = 'restaurant'

class City(models.Model):
    id = models.AutoField(primary_key=True, db_column='id')
    name = models.CharField(max_length=50L, db_column='city')
    state = models.CharField(max_length=50L, db_column='state', blank=True, null=True)
    class Meta:
        db_table = 'city'

class Cuisinetype(models.Model):
    id = models.AutoField(primary_key=True, db_column='id')
    name = models.CharField(max_length=50L, db_column='cuisine', blank=True) # Field name made lowercase.
    class Meta:
        db_table = 'cuisinetype'

class Location(models.Model):
    id = models.AutoField(primary_key=True, db_column='id')
    name = models.CharField(max_length=50L, db_column='location', blank=False, null=False)
    city = models.ForeignKey('City', related_name="location_city")
    class Meta:
        db_table = 'location'

class Hood(models.Model):
    id = models.AutoField(primary_key=True, db_column='id')
    name = models.CharField(max_length=50L, db_column='hood')
    city = models.ForeignKey('City', related_name='hood_city')
    location = models.ForeignKey('Location', related_name='hood_location')
    class Meta:
        db_table = 'hood'

class Listingrole(models.Model):
    id = models.AutoField(primary_key=True, db_column='id')
    name = models.CharField(max_length=50L, db_column='listingrole', blank=True) # Field name made lowercase.
    class Meta:
        db_table = 'listingrole'
....

最佳答案

考虑到coisine_types的概念和含义，您不必使用through关键字建立关系。当存在有关其自身关系的某些信息时，您将使用它（主要是）。

根据Django文档：


  此选项最常见的用法是当您要将多余的数据与多对多关系关联时。


请参阅此处的说明：Extra fields on many-to-many relationships

关于python - Django Models.py数据库设计反馈，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/22362123/