python - 0-23 小时军用时钟到标准时间 (hh :mm)

我将如何进行这个过程？假设有人输入“3:5”，我应该能够得到输出“3:05 AM”。或者如果有人输入“00:00”，我应该得到“12:00 AM”。如果将时间格式简单地输入为“hhmm”，我意识到有很多方法可以解决这个问题，但输入的范围可以从“h:m”、“hh:m”、“hh:m”和“hh:毫米”。所以这是非常有情况的。

def timeConvert():
    miliTime = int(input("Enter a time in hh:mm (military) format: "))
    miliTime.split(":")
    if len(miliTime) == 3:
        hours = miliTime[0]
        minutes = miliTime[2]
        if hours < 0:
            print("Hours can't be less than 0.")
    elif len(miliTime) == 4:
        if miliTime[0:2] >= 10:
            hours = militime[0:2]
            minutes = militime[3]
            if minutes < 0:
                print("Minutes can't be less than 0.")
            if minutes < 10:
                minutes = 0 + minutes
        else:
            hours = miliTime[0]
            minutes = militime[2:]
            if minutes >= 60:
                print("Too big of a number for minutes.")
    else:
        hours = miliTime[0:2]
        minutes = miliTime[3:]
    setting = AM
    if hours > 12:
        setting = PM
        hours -= 12
    print(hours + ":" + minutes + setting)

timeConvert()

最佳答案

通过 : 分割输入，最后使用格式化输出:

def timeConvert():
    miliTime = input("Enter a time in hh:mm (military) format: ")
    hours, minutes = miliTime.split(":")
    hours, minutes = int(hours), int(minutes)
    setting = "AM"
    if hours > 12:
        setting = "PM"
        hours -= 12
    print(("%02d:%02d" + setting) % (hours, minutes))

关于python - 0-23 小时军用时钟到标准时间 (hh :mm)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/31691007/