laravel - $ request-> route()在中间件中为null，如何按路由参数过滤？

Laravel 5.1弃用了Route::filter()和其他相关函数claiming in the docs that:



但是，如果您的路由过滤器访问路由参数，那么由于中间件中的$request->route()是null，您怎么用中间件替换它呢？

Route::filter('foo', function($route, $request) {
    if ($route->parameter('bar') > 1000) {
         return Redirect::route('large-bars');
    }
});

我能看到的最接近的东西是

class FooMiddleware {
    public function handle($request, Closure $next)
    {
        // Note that $request->route() is null here, as the request
        // hasn't been handled by Laravel yet.

        if ($request->segment(4) > 1000) { // ewww...
            return Redirect::route('large-bars');
        }

        return $next($request);
    }
}

但这显然比通过名称引用参数要脆弱得多。我在这里想念什么？谢谢!

最佳答案

对于在$request->route()中注册的全局中间件，App\Http\Kernel::$middleware仅为null。要访问当前路由，必须在Kernel::$routeMiddleware中注册中间件:

protected $routeMiddleware = [
    ...,
    'foo' => FooMiddleware::class,
];

Proposals to change this behavior have been rejected by the Laravel maintainers由于体系结构方面的考虑。