我使用一个fragment活动来保存一个呈现一堆产品的列表片段:
public class ProductsListActivity extends SherlockFragmentActivity {
@Override
public void onCreate(Bundle savedInstanceState) {
setTheme(R.style.Sherlock___Theme);
super.onCreate(savedInstanceState);
setContentView(R.layout.fragment_products_list);
// setFastScrollEnabled(true) ?
}
}
...
<!-- fragment_products_list.xml -->
<?xml version="1.0" encoding="utf-8"?>
<fragment xmlns:android="http://schemas.android.com/apk/res/android"
android:name="com.example.fragment.ProductsListFragment"
android:id="@+id/list_fragment"
android:layout_width="match_parent"
android:layout_height="match_parent" />
...
public class ProductsListFragment extends SherlockListFragment {
@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
// setFastScrollEnabled(true) ?
super.onViewCreated(view, savedInstanceState);
}
@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
...
}
}
我想在enable fast scrolling中找到产品列表,并找到了另一篇描述how to do this for a list activity的帖子。但是如何激活片段的快速滚动? define this in XML或通过代码都可以。
最佳答案
SherlockListFragment还具有从ListFragment继承的getListView()
方法。
getListView().setFastScrollEnabled(true);
这就是
ListFragment
内部的样子:@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
ArrayList<String> strings = new ArrayList<String>();
for(int i = 0; i < 300; i++) strings.add("Item " + i);
ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_list_item_1, strings);
setListAdapter(adapter);
getListView().setFastScrollEnabled(true);
}