我在C中创建二叉树时遇到了问题。我想我可以将图书添加到树中,在树中,将具有较后出版年份的图书添加到左边,将较早出版年份的图书添加到右边。我一直有跑步错误,我不知道为什么。
#include <stdio.h>
#include <stdlib.h>
struct book {
char* name;
int year;
};
typedef struct tnode {
struct book *aBook;
struct tnode *left;
struct tnode *right;
} BTree;
BTree* addBook(BTree* nodeP, char* name, int year){
if( nodeP == NULL )
{
nodeP = (struct tnode*) malloc( sizeof( struct tnode ) );
(nodeP->aBook)->year = year;
(nodeP->aBook)->name = name;
/* initialize the children to null */
(nodeP)->left = NULL;
(nodeP)->right = NULL;
}
else if(year > (nodeP->aBook)->year)
{
addBook(&(nodeP)->left,name,year );
}
else if(year < (nodeP->aBook)->year)
{
addBook(&(nodeP)->right,name,year );
}
return nodeP;
}
void freeBTree(BTree* books)
{
if( books != NULL )
{
freeBTree(books->left);
freeBTree(books->right);
//free( books );
}
}
void printBooks(BTree* books){
if(books != NULL){
}
}
int main(int argc, char** argv) {
BTree *head;
head = addBook(head,"The C Programming Language", 1990);
/*addBook(head,"JavaScript, The Good Parts",2008);
addBook(head,"Accelerated C++: Practical Programming by Example", 2000);
addBook(head,"Scala for the impatient",2012);*/
}
最佳答案
一个问题是您没有初始化为空:
BTree *head;
应该是
BTree *head = NULL;
我建议将编译器警告设置得更高。您的两个递归调用不正确,编译器应该对此发出警告:
addBook(&(nodeP)->left,name,year );
应该是:
addBook( nodeP->left,name,year );
从参数传递的角度来看。但是,此函数现在无法正常工作,因为在节点指针为空时添加,这意味着您不能将父节点附加到子节点,因为父指针节点已不存在。我认为逻辑应该检查适用的右/左节点,如果为空,则在例程中向右添加,否则递归调用,直到找到右/左指针为空的节点。
像这样的:
BTree *makeNode(char *name, int year)
{
// NOTE: 3 frees required for every node
BTree *nodeP = malloc( sizeof( struct tnode ) ); // 1
nodeP->aBook = malloc( sizeof(struct book) ); // 2
(nodeP->aBook)->year = year;
(nodeP->aBook)->name = malloc(strlen(name) + 1); // 3
strcpy((nodeP->aBook)->name,name);
/* initialize the children to null */
nodeP->left = NULL;
nodeP->right = NULL;
return nodeP;
}
BTree* addBook(BTree* nodeP, char* name, int year)
{
if ( nodeP == NULL )
{
nodeP = makeNode(name,year);
}
else if (year > (nodeP->aBook)->year)
{
if ( nodeP->left == NULL )
nodeP->left = makeNode(name,year);
else
addBook( nodeP->left,name,year );
}
else if(year < (nodeP->aBook)->year)
{
if ( nodeP->right == NULL )
nodeP->right = makeNode(name,year);
else
addBook( nodeP->right,name,year );
}
return nodeP;
}
void printBooks(BTree* books)
{
if (books != NULL) {
printf("book: %s %d\n",books->aBook->name,books->aBook->year);
printBooks(books->right);
printBooks(books->left);
}
}
关于c - C中的二叉树,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/12574506/