我想把单词从头到尾切分。假设,我有一些区分大小写的行(大写/小写)
Abc Defg Hijk Lmn
Xyz Lmn jkf gkjhg
我想把它们切成如下:
Abc Defg Hijk
Abc Defg
Abc
然后,我需要获取变量中的每一个切片行,以便使用它们在某个文本文件中搜索并返回整个文本:
假设我有文本:
Akggf Abc Defg Hijk fgff jfkjgk djkfkgf
Akgff Abc fgff jfkjgk djkfkgf
Akggef Abc Defg fgff jfkjgk djkfkgf
gjshgs gskk Xyz Lmn jkf
fgsgdf fkgksk Xyz Lmn
有什么建议吗?谢谢!
最佳答案
也可以使用以下代码:
dataStr = 'Abc Defg Hijk Lmn'
for word in reversed(dataStr.split()):
# do something with word
或:
dataStr = 'Abc Defg Hijk Lmn'
removeLastWord = lambda line: ' '.join([word for word in line.split()[:-1]])
dataStr = removeLastWord(dataStr)
>>> 'Abc Defg Hijk'
dataStr = removeLastWord(dataStr)
>>> 'Abc Defg'
dataStr = removeLastWord(dataStr)
>>> 'Abc'
我看过你的最新消息,认为罗曼的解决方案符合你的需要。您可以通过以下方式更新代码:
searchTxt = """Abc Defg Hijk Lmn
Xyz Lmn jkf gkjhg"""
data = """kggf **Abc Defg Hijk** fgff jfkjgk djkfkgf
Akggf **Abc ** fgff jfkjgk djkfkgf
Akggf **Abc Defg fgff jfkjgk djkfkgf
gjshgs gskk **Xyz Lmn jkf**
fgsgdf fkgksk **Xyz Lmn**"""
searchWords = []
for line in (line for line in searchTxt.split('\n') if line.strip()):
words = line.split()
searchWords.extend([' '.join(words[:i]) for i in xrange(len(words), 0, -1)])
searchWords = sorted(searchWords, key=len, reverse=True)# to look first for the longest string match
res = set([line for sword in searchWords for line in data.split('\n') if sword in line])
# OR
res = []
for line in data.split('\n'):
for sword in searchWords:
if sword in line:
res.append(line)
break
如果你需要全文:
resultText = '\n'.join(res)
关于python - python中的字符串切片,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/6623887/