是否可以将这段代码从Java 8移植到Java 7?
protected UserDetailsService userDetailsService() {
return (username) -> {
User u = crmService.findUserByUsername(username);
return new org.springframework.security.core.userdetails.User(
u.getUsername(), u.getPassword(), u.isEnabled(),
u.isEnabled(), u.isEnabled(), u.isEnabled(),
AuthorityUtils.createAuthorityList("USER", "write"));
};
}
最佳答案
您可以通过以下方式进行操作:
protected UserDetailsService userDetailsService() {
return new UserDetailsService() {
@Override
UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
User u = crmService.findUserByUsername(username);
return new org.springframework.security.core.userdetails.User(
u.getUsername(), u.getPassword(), u.isEnabled(),
u.isEnabled(), u.isEnabled(), u.isEnabled(),
AuthorityUtils.createAuthorityList("USER", "write"));
}
}
}
但是绝对,您应该考虑将其提取到普通类中,然后仅在其中返回新对象
关于spring - 将Java 8代码移植到Java 7,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/24266736/