我有以下创建警报对话框的代码,并向其中添加了两个编辑文本,但是一旦运行应用程序,将不会检索EditText中的值,并且我的应用程序会因NullPointerException而崩溃:

代码是:

AlertDialog.Builder alert = new AlertDialog.Builder(this);
        LayoutInflater inflater=this.getLayoutInflater();
        final EditText usernameInput=(EditText)findViewById(R.id.dialogusername);
        final EditText passwordInput=(EditText)findViewById(R.id.dialogpassword);
        alert.setView(inflater.inflate(R.layout.dialog,null));
        alert.setTitle("Enter Password");
        alert.setMessage("Enter password to remove the app:");
        alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            //provide user with caution before uninstalling
            //also here should be added a AsyncTask that going to read the password and once its checked the password is correct the app will be removed
            value1=usernameInput.getText().toString();
            value2=passwordInput.getText().toString();
            if(value1.equals(null)&&value2.equals(null))
            {Toast.makeText(context, "Enter username and password", Toast.LENGTH_SHORT).show();}
         }
        });
        });
        alert.show();

最佳答案

谢谢你们为回答我的问题所做的贡献,我想我已经为上面发布的问题找到了解决方案:

AlertDialog.Builder alert = new AlertDialog.Builder(MyFeedActivity.this);
        LayoutInflater inflater=MyFeedActivity.this.getLayoutInflater();
        //this is what I did to added the layout to the alert dialog
        View layout=inflater.inflate(R.layout.dialog,null);
        alert.setView(layout);
        final EditText usernameInput=(EditText)layout.findViewById(R.id.dialogusername);
        final EditText passwordInput=(EditText)layout.findViewById(R.id.dialogpassword);

而且我认为问题在于我无法在警报对话框中获取EidtText,但是通过上述代码执行此操作,一切对我都很好。

关于android - 将EditText添加到警报对话框。,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13584063/

10-15 11:51