我正在尝试使用mapstruct将不可迭代的值(即字符串)映射到字符串列表。
所以我正在使用
@Mapping(target = "abc", expression = "java(java.util.Arrays.asList(x.getY().getXyz()))")
这里
abc
是List<String>
xyz
是String
但是为此,我需要明确检查
null
。通过将不可迭代转换为可迭代,是否有更好的方法将不可迭代映射为可迭代。
最佳答案
这是不可迭代的示例:
public class Source {
private String myString;
public String getMyString() {
return myString;
}
public void setMyString(String myString) {
this.myString = myString;
}
}
public class Target {
private List<String> myStrings;
public List<String> getMyStrings() {
return myStrings;
}
public void setMyStrings(List<String> myStrings) {
this.myStrings = myStrings;
}
}
@Qualifier
@Target(ElementType.METHOD)
@Retention(RetentionPolicy.SOURCE)
public @interface FirstElement {
}
public class NonIterableToIterableUtils {
@FirstElement
public List<String> first(String in ) {
if (StringUtils.isNotEmpty(in)) {
return Arrays.asList(in);
} else {
return null;
}
}
}
@Mapper( uses = NonIterableToIterableUtils.class )
public interface SourceTargetMapper {
SourceTargetMapper MAPPER = Mappers.getMapper( SourceTargetMapper.class );
@Mappings( {
@Mapping( source = "myString", target = "myStrings", qualifiedBy = FirstElement.class )
} )
Target toTarget( Source s );
}
public class Main {
public static void main(String[] args) {
Source s = new Source();
s.setMyString("Item");
Target t = SourceTargetMapper.MAPPER.toTarget( s );
System.out.println( t.getMyStrings().get(0));
}
}