我正在尝试在python2中实现加密/解密功能。
这是加密方案：
但是，我在pycrypto库的AES CTR函数中遇到'method-wrapper' object is not iterable错误
这是堆栈跟踪：
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-5-1c44f21fcf83> in <module>()
45 l = random.randint(16,48)
46 m = random_bytes(l)
---> 47 assert specialDecryption(k, specialEncryption(k, m)) == m
<ipython-input-5-1c44f21fcf83> in specialEncryption(k, m)
7 # compute PRF
8 r = random_bytes(KEYLENGTH/8)
----> 9 prf = lengthQuadruplingPRF(k, r)
10
11 # xor
<ipython-input-4-59fb6141461b> in lengthQuadruplingPRF(k, r)
34 assert len(k) == KEYLENGTH/8
35 assert len(r) <= KEYLENGTH/8
---> 36 obj = AES.new(k, AES.MODE_CTR, counter=make_counter())
37 output = obj.encrypt(r*4)
38 return output
/usr/local/lib/python2.7/site-packages/Crypto/Cipher/AES.pyc in new(key, mode, *args, **kwargs)
204
205 kwargs["add_aes_modes"] = True
--> 206 return _create_cipher(sys.modules[__name__], key, mode, *args, **kwargs)
207
208
/usr/local/lib/python2.7/site-packages/Crypto/Cipher/__init__.pyc in _create_cipher(factory, key, mode, *args, **kwargs)
77 raise TypeError("IV is not meaningful for the ECB mode")
78
---> 79 return modes[mode](factory, **kwargs)
/usr/local/lib/python2.7/site-packages/Crypto/Cipher/_mode_ctr.pyc in _create_ctr_cipher(factory, **kwargs)
323 # 'counter' used to be a callable object, but now it is
324 # just a dictionary for backward compatibility.
--> 325 _counter = dict(counter)
326 try:
327 counter_len = _counter.pop("counter_len")
TypeError: 'method-wrapper' object is not iterable
这是代码：
if __name__ == '__main__':
k = os.urandom(KEYLENGTH/8) # generate key
l = random.randint(16,48)
m = os.urandom(l)
c = specialEncryption(k, m) ## FIRST IN THE FAILURE STACK
def specialEncryption(k, m):
... other code
# compute PRF
r = os.urandom(KEYLENGTH/8)
prf = lengthQuadruplingPRF(k, r) ## SECOND IN THE FAIL STACK
... other code
def make_counter():
import struct
def gen():
i = 0;
while True:
yield struct.pack('>QQ', 0, i)
i += 1
return gen().next
def lengthQuadruplingPRF(k, r):
# Input: 16 byte key, 16 byte value
# Output: 64 byte pseudorandom bytes
obj = AES.new(k, AES.MODE_CTR, counter=make_counter()) ## FAILS HERE
output = obj.encrypt(r*4)
return output
最佳答案
您的counter应该是可迭代的，能够初始化dict，而不是绑定方法。
我怀疑将您的make_counter函数更改为：
return gen()
从：
return gen().next
足以修复它。