我写了这样的代码。

import numpy as np
import math
p0 = np.loadtxt('A.txt', delimiter=',')
p1 = np.loadtxt('B.txt', delimiter=',')
p3 = np.loadtxt('C.txt', delimiter=',')
p = np.loadtxt('D.txt', delimiter=',')
d = 3
def distvec(p0,p1,p3,p,d):
    vec=[]
    for j in range(d):
        p0 = p0[j]
        p1 = p1[j]
        p3 = p3[j]
        p =  p[j]
        u = p0 - p3
        v = p1 - p3
        n = np.cross(u, v)
        norm = math.sqrt(np.dot(n,n))**(-1)
        n=n*norm
        p_ = p - p0
        dist_to_plane = np.dot(p_, n)
        dist=math.sqrt(dist_to_plane**2)
        vec=vec+[dist]
    return vec
distvec(p0,p1,p3,p,d)


文本文件看起来像这样。

A.txt

23.172,-20.751,31.982
23.049,-20.789,32.164
22.914,-20.952,32.14


B.txt

21.879,-17.819,34.467
21.727,-17.975,34.311
21.804,-18.267,34.462


C.txt

20.273,-20.379,34.271
20.144,-20.614,34.36
20.065,-20.765,34.408


D.txt

21.936,-19.639,33.555
21.771,-19.7,33.506
21.581,-19.955,33.543


但是,我收到一条错误消息,内容为

在第25行的文件“ test.py”中
    distvec(p0,p1,p3,p,d)
  文件“ test.py”,第17行,在distvec中
    n = np.cross(u,v)
  交叉插入文件“ /Users/Sam/anaconda3/lib/python3.6/site-packages/numpy/core/numeric.py”,行1709
    axisa = normalize_axis_index(axisa,a.ndim,msg_prefix ='axisa')
numpy.core._internal.AxisError:axisa:轴-1超出维度0数组的范围

有人知道出了什么问题吗?非常感谢!

最佳答案

np.cross(u, v)返回两个向量的叉积。在您的情况下,uv不是向量,而是维数为0的标量。这是因为您具有u = p0 - p3,其中p0p3是数组的第j个元素()。

要进行验证,可以打印p0 = p0[j]u并检查它们是标量还是一维数组(向量)。

关于python - 轴超出数组范围,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/53762183/

10-14 06:36