我想从VC1(所有餐厅视图)导航到VC2(餐厅详细信息视图),当我按“后退按钮”时,它不应该再重新加载VC1。
我该怎么解决?

func clickNameButtonCollectionView(sender: UIButton) {

        let restaurent_Id = ((self.allRecommendedRestaurent[sender.tag]  as AnyObject).value(forKey: "id") as AnyObject) as? Int

        let obj = self.storyboard?.instantiateViewController(withIdentifier: "ResturantDetailsController") as! ResturantDetailsController
        obj.restaurent_ID = restaurent_Id!
        self.navigationController?.pushViewController(obj, animated: true)
    }


@IBAction func backPressed(_ sender: Any) {
        self.navigationController?.popViewController(animated: true)
    }

补充:
override func viewDidLoad() {
        super.viewDidLoad()

        self.refreshControl.addTarget(self, action: #selector(self.reloadJoinedData), for: UIControlEvents.valueChanged)
        self.mainScrollView?.addSubview(refreshControl)

        self.appDel.apiManager.setCurrentViewController(vc: self)

        // Do any additional setup after loading the view.

        resturantTable.delegate = self
        resturantTable.dataSource = self
        resturantTable.bounces = false
        resturantcollection.delegate = self
        resturantcollection.dataSource = self
        resturantcollection.bounces = false

最佳答案

按下后退按钮后,可以使用块执行任何操作。遵循以下代码
1)在ResturantDetailsController中创建块

var back_block : (() -> Void)? = nil

2)更新后退按钮操作backPressed
@IBAction func backPressed(_ sender: Any) {
    if let action = back_block {
        action()
    }
    self.navigationController?.popViewController(animated: true)
}

3)现在在VC1中创建ResturantDetailsController对象。
    let obj = ResturantDetailsController.loadController()
    obj.back_block = {
        //reload Your TableView
    }
    obj.restaurent_ID = restaurent_Id!
    self.navigationController?.pushViewController(obj, animated: true)

关于swift - 从CV2单击时不要重新加载VC1-Swift,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/54215641/

10-11 14:25