c - 如何使此代码运行？

我似乎无法在代码中找到问题。似乎一切都很好。我应该输出两个整数的积和。

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>

main() {


int number1, number2, productResult, sumResult;

printf("Enter first number: ");
scanf("%i", &number1);
productResult = number1 * number2;

printf("Enter second number: ");
scanf("%i", &number2);
sumResult = number1 + number2;

printf("The product is: %i \n", productResult);
printf("The sum is:s %i \n", sumResult);

system("pause");
} // end of main

最佳答案

我建议您要么获得更好的编译器，要么倾听来自编译器的警告：

blah.c:5:1: warning: type specifier missing, defaults to 'int' [-Wimplicit-int]
main() {
^
blah.c:10:31: warning: variable 'number2' is uninitialized when used here [-Wuninitialized]
    productResult = number1 * number2;
                              ^~~~~~~
blah.c:6:25: note: initialize the variable 'number2' to silence this warning
    int number1, number2, productResult, sumResult;
                        ^
                         = 0
2 warnings generated.

在要求用户提供其内容之前，您正在使用number2。

关于c - 如何使此代码运行？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/39442867/