c++ - 我的三角三元组程序有问题

我的程序应该列出1-500之间的所有直角三角形三元组。它不应重复相同的三角形。例如3、4、5与4、3、5相同，只应显示第一个。我还应该在程序末尾有一个计数器，该计数器显示找到了多少个三角形。到目前为止，这就是我所拥有的。当前没有显示正确数量的三角形，并且计数器无法正常工作。谢谢

// Naming

int counter;

// For loops and nested for loops

{
       // Makes sure side A starts at 1 and is less than 500
for (int a = 1; a <= 500; a++)
{
       // Makes sure side B starts at 1 and is less than 500
    for (int b = 1; b <= 500; b++)
    {
       // Makes sure side C starts at 1 and us kess than 500
        for (int c = 1; c <= 500; c++)
        {
       // If A squared + B squared = C squared and C squared, A, and B -->
       // are all less than or equal to 500 then display the answer
            if ((a*a)+(b*b) == c*c & a & b <= 500) {
            // This is my counter I cannot seem to get it to work properly
            // More info about counter at bottom
            counter++;
                cout << a << ", " << b << ", " << c << endl;
            }
        }
    }
}
}

cout << endl;
// Displaying counter
cout << counter << endl << endl ;

system("PAUSE");
return EXIT_SUCCESS;
}

最佳答案

以下行将无法满足您的期望：

// If A squared + B squared = C squared and C squared, A, and B -->
// are all less than or equal to 500 then display the answer
    if ((a*a)+(b*b) == c*c & a & b <= 500) {
                             ^^^^^^^^^^^^

更改为：

if ((a*a)+(b*b) == c*c && a <= 500 && b <= 500) {

ps：正如@ Code-Apprentice进一步说明的那样，a <= 500 && b <= 500循环已经保证了for，因此可以将其简化为：

if ((a*a)+(b*b) == c*c) {

关于c++ - 我的三角三元组程序有问题，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/26269627/