我有两个列表和一个数组:
owners = [ 'Bill', 'Ann', 'Sarah']
dog = ['shepherd', 'collie', 'poodle', 'terrier']
totals = [[5, 15, 3, 20],[3,2,16,16],[20,35,1,2]]
我想用这些做一个嵌套的字典。
dict1 = {'Bill': {'shepherd': 5, 'collie': 15, 'poodle': 3, 'terrier': 20},
'Ann': {'shepherd': 3, 'collie': 2, 'poodle': 16, 'terrier': 16},
'Sarah': {'shepherd': 20, 'collie': 35, 'poodle': 1, 'terrier': 2}
}
我最接近的尝试:
totals_list = totals.tolist()
dict1 = dict(zip(owners, totals_list))
我找不到找到所需嵌套字典的方法。有什么建议么?
最佳答案
main_dict = {}
for owner, total in zip(owners, totals):
main_dict[owner] = {}
for key, value in zip(dog, total):
main_dict[owner][key] = value
您也可以使用
dict comprehension
将它写成一行:main_dict = {owner: dict(zip(dog, total)) for owner, total in zip(owners, totals)}