Class ProdsTransformer:
def __init__(self):
self.products_lookup_hmap = {}
self.broadcast_products_lookup_map = None
def create_broadcast_variables(self):
self.broadcast_products_lookup_map = sc.broadcast(self.products_lookup_hmap)
def create_lookup_maps(self):
// The code here builds the hashmap that maps Prod_ID to another space.
pt = ProdsTransformer ()
pt.create_broadcast_variables()
pairs = distinct_users_projected.map(lambda x: (x.user_id,
pt.broadcast_products_lookup_map.value[x.Prod_ID]))
我收到以下错误:
如何处理广播变量的任何帮助将是巨大的!
最佳答案
通过在map
lambda中引用包含广播变量的对象,Spark将尝试序列化整个对象并将其发送给worker。由于对象包含对SparkContext的引用,因此会出现错误。代替这个:
pairs = distinct_users_projected.map(lambda x: (x.user_id, pt.broadcast_products_lookup_map.value[x.Prod_ID]))
试试这个:
bcast = pt.broadcast_products_lookup_map
pairs = distinct_users_projected.map(lambda x: (x.user_id, bcast.value[x.Prod_ID]))
后者避免了对对象的引用(
pt
),因此Spark只需要发送广播变量。关于python - Spark : Broadcast variables: It appears that you are attempting to reference SparkContext from a broadcast variable,操作或转换,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/31508689/