我正在尝试做一个简单的reshape
,使test
看起来像这样:
a_estimate, a_tstat, b_estimate, b_tstat
1, 3, 2, 4
这是我尝试的代码:
require(reshape2)
test = data.frame(cf=c("a", "b"), estimate=c(1,2), tstat=c(3,4))
m = melt(test, id.vars="cf")
d = dcast(m, formula = . ~ cf + variable)
Error: nrow(res$labels[[1]]) == nrow(data) is not TRUE
这里发生了什么?
> sessionInfo()
R version 2.15.2 (2012-10-26)
Platform: x86_64-unknown-linux-gnu (64-bit)
locale:
[1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C
[3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8
[5] LC_MONETARY=en_US.UTF-8 LC_MESSAGES=en_US.UTF-8
[7] LC_PAPER=C LC_NAME=C
[9] LC_ADDRESS=C LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_US.UTF-8 LC_IDENTIFICATION=C
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] reshape2_1.2.2
loaded via a namespace (and not attached):
[1] plyr_1.8 stringr_0.6.2
最佳答案
也许您的问题是您实际上只剩下零个“行”变量(即,您完全不希望在转换公式的LHS上有任何东西)。此解决方法(添加虚拟变量)可能有帮助?
d = dcast(cbind(x=1,m), formula = x ~ cf + variable)
关于r - 使用reshape2在R中进行简单的重塑会导致错误,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/16655489/