我有一个在命令行中使用主义生成的实体。如下-
/**
* @var string
*
* @ORM\Column(name="COUNTRY_ID", type="string", length=2)
*/
private $cOUNTRYID;
在数据库中,列名称为
COUNTRY_ID
,SQL结果将为asoc。以COUNTRY_ID
为键,名称为值的数组。我的要求是将SQL结果的显示名称设置为驼峰式。例如,
COUNTRY_ID
应该为countryId
。教义文件中是否有可用的配置可用于执行此操作? 最佳答案
您必须实施一种命名策略来获取camelCase自动生成的列名,如explained in Doctrine documentation。
创建一个类以获取您的列名CamelCaseNamingStrategy.php的camelCase名称:
<?php
class CamelCaseNamingStrategy implements NamingStrategy
{
public function classToTableName($className)
{
return 'cc_' . substr($className, strrpos($className, '\\') + 1);
}
public function propertyToColumnName($propertyName)
{
return $propertyName;
}
public function referenceColumnName()
{
return 'id';
}
public function joinColumnName($propertyName, $className = null)
{
return strtolower($propertyName) . ucwords($this->referenceColumnName());
}
public function joinTableName($sourceEntity, $targetEntity, $propertyName = null)
{
return strtolower($this->classToTableName($sourceEntity)) . ucwords($this->classToTableName($targetEntity));
}
public function joinKeyColumnName($entityName, $referencedColumnName = null)
{
return strtolower($this->classToTableName($entityName)) . ($referencedColumnName ?: ucwords($this->referenceColumnName()));
}
}
然后将此新类注册为服务,并将其添加到您的config.yml中:
orm:
#...
entity_managers:
default
naming_strategy: my_bundle.camel_case_naming_strategy.default
关于symfony - 如何使教义生成的列名显示在教义2 symfony中的驼峰式案例中?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/40904550/