我几个月来一直在快速开发应用程序,但我不知道如何将数据传递到图表。因此,基本上我所拥有的是一个内部带有数组的视图控制器以及一个包含图表的UIView。我想做的是,UIView中的图形在ViewController中绘制数组。所以我想要的是将视图控制器中数组dataMoneyTracker1中的数据传递到UIView中的数组graphPoints,或者我可以从uiview中访问视图控制器中的数组。

感谢您的回答!

这是我的代码:

视图控制器

import UIKit

class GonDetail2ViewController: UIViewController {
var dataMoneyTracker1 = [Int]()
@IBOutlet var View1: UIView!

}


UIVIEW

import UIKit

class GonGraphUIView: UIView {


    var graphPoints = [Int]()

    override func drawRect(rect: CGRect) {
        let width = rect.width
        let height = rect.height

        let margin:CGFloat = 20.0
        let columnXPoint = { (column:Int) -> CGFloat in
            //Calculate gap between points
            let spacer = (width - margin*2 - 4) /
                CGFloat((self.graphPoints.count - 1))
            var x:CGFloat = CGFloat(column) * spacer
            x += margin + 2
            return x



    }

        let topBorder:CGFloat = 60
        let bottomBorder:CGFloat = 50
        let graphHeight = height - topBorder - bottomBorder
        let maxValue = graphPoints.maxElement()
        let columnYPoint = { (graphPoint:Int) -> CGFloat in
            var y:CGFloat = CGFloat(graphPoint) /
                CGFloat(maxValue!) * graphHeight
            y = graphHeight + topBorder - y // Flip the graph
            return y
        }

        UIColor.whiteColor().setFill()
        UIColor.whiteColor().setStroke()

        //set up the points line
        let graphPath = UIBezierPath()
        //go to start of line
        graphPath.moveToPoint(CGPoint(x:columnXPoint(0),
            y:columnYPoint(graphPoints[0])))

        //add points for each item in the graphPoints array
        //at the correct (x, y) for the point
        for i in 1..<graphPoints.count {
            let nextPoint = CGPoint(x:columnXPoint(i),
                y:columnYPoint(graphPoints[i]))
            graphPath.addLineToPoint(nextPoint)
        }

        graphPath.stroke()

        graphPath.lineWidth = 2.0
        graphPath.stroke()

        //Draw the circles on top of graph stroke
        for i in 0..<graphPoints.count {
            var point = CGPoint(x:columnXPoint(i), y:columnYPoint(graphPoints[i]))
            point.x -= 5.0/2
            point.y -= 5.0/2

            let circle = UIBezierPath(ovalInRect:
                CGRect(origin: point,
                    size: CGSize(width: 5.0, height: 5.0)))
            circle.fill()
        }

    /*
    // Only override drawRect: if you perform custom drawing.
    // An empty implementation adversely affects performance during animation.
    override func drawRect(rect: CGRect) {
        // Drawing code
    }
    */

}
}

最佳答案

可以使用以下变量重新定义UIViewController:

@IBOutlet var View1: GonGraphUIView!


并在GonGraphUIView

var graphPoints:[Int]?


然后在drawRect

if let graphPoints = graphPoints {
    // draw the graph
} else { do nothing }


所以UIViewController可以说

View1.graphPoints = dataMoneyTracker1
View1.setneedsDisplay()

10-07 19:05
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