ios - 无法在UIPickerView中强制转换类型异常的值

我正在实现一个从parse.com对象填充的UIPickerView。
我想在apickerView中显示从TextField中选择的行字符串。
在执行时，当用户选择一行时，TextField会显示文本，但当试图将TextField文本传递给另一行时，应用程序会启动一个异常：
无法强制转换类型的值
这是代码：

class CitaServicio3: UIViewController,UITextFieldDelegate,UIPickerViewDataSource,UIPickerViewDelegate {
    var receivedNombre: String = ""
    var receivedEmail: String = ""
    var receivedCelular: String = ""
    var receivedTelefono: String = ""
    var receivedFecha: String = ""
    var receivedHora: String = ""

    @IBOutlet weak var vehiculoPickerView: UIPickerView!
    @IBOutlet var vehiculoTextField:UITextField!

    var pickerString:NSMutableArray = []

    override func viewDidLoad() {
        super.viewDidLoad()

        print("receivedNombre=",receivedNombre)
        print("receivedEmail=",receivedEmail)
        print("receivedCelular=",receivedCelular)
        print("receivedTelefono=",receivedTelefono)
        print("receivedFecha=",receivedFecha)
        print("receivedHora=",receivedHora)

        let query = PFQuery(className: "autos")
        query.findObjectsInBackgroundWithBlock({ (objects : [PFObject]?, error: NSError?) -> Void in
            if error == nil {
                for object in objects! {
                    print (object["modelo"])
                    self.pickerString.addObject(object["modelo"] as! String)
                }
            }
             self.vehiculoPickerView.reloadAllComponents()
        })
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int
    {
        return 1
    }

    // returns the # of rows in each component..
    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int
    {
        return self.pickerString.count
    }


    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String?
    {
        return self.pickerString[row] as? String
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int)
{
    self.vehiculoTextField.text  = self.pickerString[row] as? String
}

    @IBAction func continuarButton(sender: AnyObject)
    {
        let vehiculoCita = vehiculoTextField.text
            if (vehiculoCita!.isEmpty ){
            let myAlert = UIAlertController(title: "Faltan datos", message: "Su vehiculo es obligatorio", preferredStyle: UIAlertControllerStyle.Alert)
            let OKAlert = UIAlertAction(title: "Reintentar", style: UIAlertActionStyle.Default, handler: nil)
            myAlert.addAction(OKAlert)
            self.presentViewController(myAlert, animated: true, completion: nil)
            return
        }
        [self .performSegueWithIdentifier("cita3a4", sender: self)]
    }

    override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!) {

        print (segue.identifier)
        print (vehiculoTextField.text)
        if "cita3a4" == segue.identifier {
            let cita4: CitaServicio4 = segue.destinationViewController as! CitaServicio4

            cita4.receivedNombre = receivedNombre
            cita4.receivedEmail = receivedEmail
            cita4.receivedCelular = receivedCelular
            cita4.receivedTelefono = receivedTelefono
            cita4.receivedFecha = receivedFecha
            cita4.receivedVehiculo = vehiculoTextField.text!
        }
    }

密码有什么问题？

最佳答案

你是说：

let cita4: CitaServicio4 = segue.destinationViewController as! CitaServicio4

但是这个segue的目的地视图控制器不是CitaServicio4。（事实上，这是一个CitaServicio3。）因此，当强制强制转换不可能时，您会在运行时崩溃。
似乎你故事板里的东西结构并不是你想象的那样。重新检查您的segue，特别是它们的脚本标识符和它们指向的视图控制器的类。

关于ios - 无法在UIPickerView中强制转换类型异常的值，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/34829794/