我希望在下面的场景中对父类(super class)的字段进行解码,但事实并非如此。怎么做才能让它发挥作用?
输入:
<?xml version="1.0" encoding="UTF-8"?>
<a>my text</a>
捆绑:
<?xml version="1.0"?>
<xml-bindings
xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="test">
<java-types>
<java-type name="SubClass">
<xml-root-element name="a"/>
<java-attributes>
<xml-element java-attribute="text" xml-path="text()" />
</java-attributes>
</java-type>
</java-types>
</xml-bindings>
类(class):
public class SuperClass {
private String text;
public String getText() {
return text;
}
public void setText(String text) {
this.text = text;
}
}
public class SubClass extends SuperClass { }
演示:
Map<String, Object> jaxbContextProperties = new HashMap<String, Object>(1);
jaxbContextProperties.put(JAXBContextProperties.OXM_METADATA_SOURCE, "bindings.xml");
JAXBContext jaxbContext = JAXBContextFactory.createContext(new Class[] {SuperClass.class}, jaxbContextProperties);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
SuperClass superClass = (SuperClass)unmarshaller.unmarshal(new File("input.xml"));
System.out.println(superClass.getText());
输出:
[EL Warning]: 2013-07-31 15:09:16.602--Ignoring attribute [text] on class [SubClass] as no Property was generated for it.
null
最佳答案
映射需要在它所属的类上进行。
选项 #1 - 在 SuperClass
上映射 SubClass
属性
如果要将父类(super class)属性映射为子类的一部分,则需要在 java-type
元素上标记父类 transient 。
bindings.xml
<?xml version="1.0"?>
<xml-bindings
xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="forum17981925">
<java-types>
<java-type name="SuperClass" xml-transient="true"/>
<java-type name="SubClass">
<xml-root-element/>
<java-attributes>
<xml-element java-attribute="text" xml-path="text()" />
</java-attributes>
</java-type>
</java-types>
</xml-bindings>
选项 #2 - 在
SuperClass
上映射 SuperClass
属性或者,您可以将
text
属性映射到 SuperClass
上,然后该映射由 SubClass
继承。bindings.xml
<?xml version="1.0"?>
<xml-bindings
xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="forum17981925">
<java-types>
<java-type name="SuperClass">
<java-attributes>
<xml-element java-attribute="text" xml-path="text()" />
</java-attributes>
</java-type>
<java-type name="SubClass">
<xml-root-element/>
</java-type>
</java-types>
</xml-bindings>
演示代码
可以运行以下演示代码来证明这两个选项都有效:
input.xml
<subClass>Hello World</subClass>
演示
import java.io.File;
import java.util.*;
import javax.xml.bind.*;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
import org.eclipse.persistence.jaxb.JAXBContextProperties;
public class Demo {
public static void main(String[] args) throws Exception {
Map<String, Object> jaxbContextProperties = new HashMap<String, Object>(1);
jaxbContextProperties.put(JAXBContextProperties.OXM_METADATA_SOURCE, "bindings.xml");
JAXBContext jaxbContext = JAXBContextFactory.createContext(new Class[] {SuperClass.class}, jaxbContextProperties);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
SuperClass superClass = (SuperClass)unmarshaller.unmarshal(new File("input.xml"));
System.out.println(superClass.getText());
}
}
输出
Hello World
关于inheritance - EclipseLink MOXy : Superclass fields are not set when unmarshaling,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/17981925/