我学的很快。我一直在操场上尝试。我不知道为什么字符串没有在这里大写。还是有其他方法可以直接将数组内的字符串大写?

这是我的代码。

var dogNames = ["Sean", "fido", "Sarah", "Parker", "Walt", "abby", "Yang"]

for index in 0..<dogNames.count {
    var dogName = dogNames[index].capitalizedString
    dogNames.removeAtIndex(index)
    dogNames.append(dogName)
}

当我尝试再次显示变量dogNames时。里面的字符串没有大写。

最佳答案

更新: Xcode 8.2.1•Swift 3.0.2

var dogNames = ["Sean", "fido", "Sarah", "Parker", "Walt", "abby", "Yang"]

for (index, element) in dogNames.enumerated() {
    dogNames[index] = element.capitalized
}

print(dogNames)   // "["Sean", "Fido", "Sarah", "Parker", "Walt", "Abby", "Yang"]\n"

这是使用map()的典型情况:
let dogNames1 = ["Sean", "fido", "Sarah", "Parker", "Walt", "abby", "Yang"].map{$0.capitalized}
filter()示例:
let dogNamesStartingWithS = ["Sean", "fido", "Sarah", "Parker", "Walt", "abby", "Yang"].filter{$0.hasPrefix("S")}

dogNamesStartingWithS   // ["Sean", "Sarah"]

您可以将两者结合使用:
let namesStartingWithS = ["sean", "fido", "sarah", "parker", "walt", "abby", "yang"].map{$0.capitalized}.filter{$0.hasPrefix("S")}

namesStartingWithS   // ["Sean", "Sarah"]

如果需要,您还可以使用sort方法(或者如果您不想改变原始数组,则使用sort方法)来按字母顺序对结果进行排序:
let sortedNames = ["sean", "fido", "sarah", "parker", "walt", "abby", "yang"].map{$0.capitalized}.sorted()

sortedNames  // ["Abby", "Fido", "Parker", "Sarah", "Sean", "Walt", "Yang"]

关于ios - 如何直接将数组中的所有字符串大写?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/28690190/

10-14 13:12
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