java - 从结果中消除零(Java)

好吧，所以我建立了印度卢比的面额柜台。说，如果您输入Rs。 3453，它给出以下输出：

1000卢比笔记：3
500卢比纸币：0
100卢比：4
50卢比注：1
Rs 20笔记：0
10卢比笔记：0
5卢比笔记：0
2卢比硬币：1
1卢比硬币：1

但是我想要这个输出并消除所有零，

1000卢比笔记：3
100卢比：4
50卢比注：1
2卢比硬币：1
1卢比硬币：1

这是我的代码：

import java.io.*;
import javax.swing.JOptionPane;

public class denom {
public static void main(String[] args) throws IOException{

    String totalRsString;
    int totalRs;
    totalRsString = JOptionPane.showInputDialog(null, "Enter amount to be converted",   "Denomination Conversion", JOptionPane.INFORMATION_MESSAGE);
    totalRs = Integer.parseInt(totalRsString);
    //Calculations begin here
    int thousand, fh, h, f, twenty, t, fi, tw, o;
    thousand = totalRs/1000;
    int bal = totalRs - (1000*thousand);
    fh = bal/500;
    bal = bal - (500*fh);
    h = bal/100;
    bal = bal - (100 * h);
    f = bal/50;
    bal = bal - (50*f);
    twenty = bal/20;
    bal = bal - (20*twenty);
    t = bal/10;
    bal = bal-(10*t);
    fi = bal/5;
    bal = bal - (5*fi);
    tw = bal/2;
    bal = bal - (2*tw);
    o = bal/1;
    bal = bal - (1*o);
    //End of calculation
    //Print work.
    JOptionPane.showMessageDialog(null, "Total Entered is Rs." + totalRsString + "\n" +     "\nThousand rupee notes: " + thousand + "\nFive Hundred Notes: " + fh + "\nHundred notes: " + h + "\nFifty notes: " + f + "\nTwenty notes: " + twenty + "\nTen notes: " + t + "\nFive notes: " + fi +
    "\nTwo coins: " + tw + "\nOne coins: " + o);
}
}

最佳答案

可以将... + ... + ...（see Javadoc for StringBuilder）组合成多个语句，而不必将字符串构建为形式为java.lang.StringBuilder的单个表达式。例如，如下所示：

JOptionPane.showMessageDialog(null, "foo: " + 17 + "\n" + "bar" + 18 + "\n");

可以这样重写：

StringBuilder message = new StringBuilder();
message.append("foo: ").append(17).append("\n");
message.append("bar: ").append(18).append("\n");
JOptionPane.showMessageDialog(null, message.toString());

通过使用这种方法，可以将任何单独的“ append”语句包装在if块中，以确保在将值添加到字符串之前，该值不为零。