php - CakePHP的模型关联

我是CakePHP的新手，在弄清楚如何设置模型关联方面有些麻烦。

假设我有3个表格：付款，预订和Reservation_details，包含以下数据

table reservations
id  |  confirmation_number   |   guest_id
1         123                        1

table reservation_details -a reservation can have multiple entries (multiple rooms)
id  |  reservation_id   |   date     |  time   | room_id    |   rate
 2           1            2014-18-04    13:00        1           9.99
 3           1            2014-18-04    13:00        2           4.99

table payments - many payments for one reservation can be made
id  |   reservation_id  |   payment_amount    |  payment_type   |   guest_id
 4            1                    14.98                Cash             1

这是我的模特协会

 //Reservation model
 public $hasMany = array('ReservationDetail', 'Payment');

 //ReservationDetail model
 public $belongsTo = array('Reservation');

 //Payment model
 public $belongsTo = array('Reservation');
 public $hasMany = array('ReservationDetail' => array('foreignKey' => 'reservation_id'));

我正在尝试做的是能够搜索付款，并且它将为该付款返回相应的Reservation和Reservation_details。因此，它将从reservation_details中获取共享相同reservation_id的所有记录。现在，保留已返回，但reserve_details返回为空

以下搜索从付款和预订返回信息，但从Reservation_details返回空数组。

$payment = $this->Payment->find('all',array(
                                      'conditions' => array(
                                         'Payment.guest_id' => '1'
                                        )
                                ));

我几乎可以肯定的是，它正在加入payments.id = payments.reservation_id上的reservation_details表，而不是payments.reservation_id = Reservation_details.reservation_id。当我手动将payments.id更改为1（reservation_id值）时，将返回reservation_details。

我相信我要实现的MySQL查询就像

SELECT reservations.*, reservation_details.*, payments.* from payments
INNER JOIN reservations on reservations.id = payments.reservation_id
INNER JOIN reservation_details on reservation_details.reservation_id = payments.reservation_ID
WHERE payments.guest_id = '1'

最佳答案

Payment.php

将可包含的行为添加为-

public $actsAs = array('Containable');

PaymentsController.php

$payments = $this->Payment->find('all', array(
                                            'conditions' => array(
                                                'Payment.guest_id' => '1'
                                            ),
                                            'contain' => array(
                                                'Reservation' => array(
                                                    'ReservationDetail'
                                                )
                                            )

));

debug($payments);

关于php - CakePHP的模型关联，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/23164716/