c++ - 该程序拒绝进入第二条语句

我不太喜欢编程，实际上我已经开始并给自己做作业了，可以随意说我是菜鸟。

这是问题陈述：

您可以种植两种种子之一（蓝色或红色）
在温度高于75度的土壤中种植时，红色会长成花，否则，如果温度符合条件，则它将长成蘑菇，要在花朵上种植花，在潮湿的土壤中种植红色种子会产生向日葵，然后种植红色种子。在干燥的土壤中会产生dandiliom。
在土壤温度下，蓝色种子会在花朵中生长。从60-70 F度。或者是蘑菇。在潮湿的土壤中，在干燥的蒲公英中

这是代码：

*

#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
int main()
{
    string plantedSeed = "";
    string seedColor = "";
    cout << "What color will the seed be? (red/blue): \n";
    getline(cin, seedColor);
    int soilTemperature = 0;
    cout << "What temperature will the soil have?\n";
    cin >> soilTemperature;
    if (seedColor == "red")
    {
        if (soilTemperature >= 75)
            plantedSeed = "mushroom";
        if (soilTemperature < 75)
        {
            string seedState = "";
            cout << "Enter the state of the soil in which the seed is plantet to (wet/dry)\n";
            getline(cin, seedState);
            if (seedState == "wet")
                plantedSeed = "sunflower";
            if (seedState == "dry")
                plantedSeed = "dandelion";
        }
    }
    if(seedColor == "blue")
    {
        if (soilTemperature >= 60 && soilTemperature <= 70)
            plantedSeed = "mushroom";
        else
        {
            string seedState = "";
            cout << "Enter the state of the soil in which the seed is plantet to (wet/dry)\n";
            getline(cin, seedState);
            if (seedState == "wet")
                plantedSeed = "dandelion";
            if (seedState == "dry")
                plantedSeed = "sunflower";
        }
    }
    cout << "The planted seed has transformed into: " << endl;
    cout << plantedSeed << endl;
    system("pause");
    return 0;
}

*
问题在于程序拒绝进入if（soilTemperature

if (seedColor == "red")
    {
        if (soilTemperature >= 75)
            plantedSeed = "mushroom";
        if (soilTemperature < 75)
        {
            string seedState = "";
            cout << "Enter the state of the soil in which the seed is plantet to (wet/dry)\n";
            getline(cin, seedState);
            if (seedState == "wet")
                plantedSeed = "sunflower";
            if (seedState == "dry")
                plantedSeed = "dandelion";
        }
    }

蓝色也一样。

最佳答案

读取温度后，您需要忽略\n：

cout << "What temperature will the soil have?\n";
cin >> soilTemperature;
cin.ignore();

读取温度后，在标准输入中有此行尾。然后，在下面的getline中读取空行。当然，您错了，程序进入第二条语句，但是getline直接以空行结束。

关于c++ - 该程序拒绝进入第二条语句，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/38657195/