我正在遍历具有以下结构的json对象:
var my_products = {
"products": [
{
"title": "Product 1",
"id": 001,
"stock_quantity": 0,
"in_stock": false
},
{
"title": "Product 2",
"id": 002,
"stock_quantity": 0,
"in_stock": false
},
{
"title": "Product 3",
"id": 003,
"stock_quantity": 1,
"in_stock": true
},
{
"title": "Product 4",
"id": 004,
"stock_quantity": 1,
"in_stock": true
}
]
};
我可以使用以下代码遍历对象:
for(var i=0; i<my_products.products.length; i++) {
var product = my_products.products[i];
console.log(product);
console.log('in_stock:',product.in_stock);
}
您知道如何遍历每条具有
"stock_quantity": 1 and "in_stock": true
属性的产品的记录吗?在上面的示例中,有2个产品记录具有“
stock_quantity": 1
属性(非零数量) 最佳答案
只需使用filter
条件即可迭代和if
数据。
var my_products = {
"products": [
{
"title": "Product 1",
"id": 001,
"stock_quantity": 0,
"in_stock": false
},
{
"title": "Product 2",
"id": 002,
"stock_quantity": 0,
"in_stock": false
},
{
"title": "Product 3",
"id": 003,
"stock_quantity": 1,
"in_stock": true
},
{
"title": "Product 4",
"id": 004,
"stock_quantity": 1,
"in_stock": true
}
]
};
var filterData = [];
$.each(my_products.products, function(){
if (this.in_stock && this.stock_quantity === 1) {
filterData.push(this);
}
});
console.log(filterData);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>