ios - 如何将具有十六进制值的NSString转换为Char- objective-c

我有一个NSString @“ 460046003600430035003900”，它代表十六进制颜色FF6C59。

如何从上述格式的字符串中获取十六进制颜色：

例如：
460046003500430032003000 = FF5C20

300030004200350033004500 = 00B53E

最佳答案

#import <Foundation/Foundation.h>

@interface WeirdFormatDecoder : NSObject
@end

@implementation WeirdFormatDecoder

+(NSString*) decode:(NSString*)string
{
    if (!string) return @"";
    NSAssert([string length]%2==0, @"bad format");
    NSMutableString *s = [NSMutableString new];
    for (NSUInteger i=0; i<[string length]-2; i=i+2) {
        char c = [[string substringWithRange:NSMakeRange(i, 2)] integerValue];
        if (c==0) continue;
        else if (c<41){
            [s appendFormat:@"%c",[@"0123456789" characterAtIndex:c-30]];
        } else {
            [s appendFormat:@"%c",[@"ABCDEF" characterAtIndex:c-41]];
        }
    }
    return s;
}

@end

int main(int argc, char *argv[]) {
    @autoreleasepool {
        NSLog(@"%@",[WeirdFormatDecoder decode:@"460046003600430035003900"]); // FF6C59
        return EXIT_SUCCESS;
    }
}

关于ios - 如何将具有十六进制值的NSString转换为Char- objective-c ，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/14899399/