我有两个 xts 时间序列。其中的一个小样本:
ts1
[,1]
2009-05-06 00:00:00 38.414
2009-05-06 00:15:00 45.079
2009-05-06 00:30:00 38.878
2009-05-06 00:45:00 49.889
2009-05-06 01:00:00 41.270
2009-05-06 01:15:00 41.050
2009-05-06 01:30:00 38.951
2009-05-06 01:45:00 39.854
2009-05-06 02:00:00 37.803
2009-05-06 02:15:00 42.930
ts2
[,1]
2009-05-06 00:00:00 406.887
2009-05-06 00:15:00 413.298
2009-05-06 00:30:00 409.353
2009-05-06 00:45:00 412.312
2009-05-06 01:00:00 409.353
2009-05-06 01:15:00 415.271
2009-05-06 01:30:00 416.257
2009-05-06 01:45:00 416.257
2009-05-06 02:00:00 416.257
2009-05-06 02:15:00 419.216
现在我想针对 ts2 创建一个散点图 ts1。根据 CRAN 的文档(我也在 stackoverflow 中以同样的方式找到了示例)它应该像这样工作:
plot(ts1, ts2) 。但我得到一个错误。plot(ts1,ts2)
# Error in plot(xycoords$x, xycoords$y, type = type, axes = FALSE, ann = FALSE, :
# object 'xycoords' not found
怎么了？它适用于带有
ts 符号的普通 ~ ，但这在 xts 中不起作用。我也试过 plot(ts1[, 1], ts2[, 1]) 。 最佳答案
最简单的做法是直接调用 plot.zoo ，而不是让 plot 泛型分派(dispatch)到 plot.xts 。
ts1 <-
structure(c(38.414, 45.079, 38.878, 49.889, 41.27, 41.05, 38.951,
39.854, 37.803, 42.93), .Dim = c(10L, 1L), index = structure(c(1241586000,
1241586900, 1241587800, 1241588700, 1241589600, 1241590500, 1241591400,
1241592300, 1241593200, 1241594100), tzone = "", tclass = c("POSIXct",
"POSIXt")), class = c("xts", "zoo"), .indexCLASS = c("POSIXct",
"POSIXt"), tclass = c("POSIXct", "POSIXt"), .indexTZ = "", tzone = "")
ts2 <-
structure(c(406.887, 413.298, 409.353, 412.312, 409.353, 415.271,
416.257, 416.257, 416.257, 419.216), .Dim = c(10L, 1L),
index = structure(c(1241586000, 1241586900, 1241587800, 1241588700,
1241589600, 1241590500, 1241591400, 1241592300, 1241593200, 1241594100),
tzone = "", tclass = c("POSIXct", "POSIXt")), class = c("xts", "zoo"),
.indexCLASS = c("POSIXct", "POSIXt"), tclass = c("POSIXct", "POSIXt"),
.indexTZ = "", tzone = "")
plot.zoo(ts1, ts2)
关于r - 两个 xts 时间序列的散点图，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/31656380/