如何从调用插件的集合中（而不是从DOM本身中）删除没有id属性的元素？
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<div class="attach"></span>
jQuery调用和插件：
$('.attach').attach();
(function($) {
$.fn.attach = function(options) {
// Remove elements (without id) on which the plugin was invoked
var valid = ???;
// Loop each valid element (with id attribute) and process
valid.each(function() {
});
return this; // Maintain chainability
};
})(jQuery);
最佳答案
使用.filter删除没有ID的元素。
(function($) {
$.fn.attach = function(options) {
// Remove elements (without id) on which the plugin was invoked
var valid = this.filter(function() { return !!this.id; });
// Loop each valid element (with id attribute) and process
valid.each(function() {
});
return this; // Maintain chainability
};
})(jQuery);
$('.attach').attach();
http://jsfiddle.net/5Kn9W/2/
或
var valid = this.not(':not([id])');-http://jsfiddle.net/5Kn9W/1/关于jquery - 从jQuery选择中删除没有ID的元素？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/9034519/