我无法解决此错误:
org.xmlpull.v1.XmlPullParserException:预期:START_TAG {http://www.w3.org/2001/12/soap-envelope}信封(位置:java.io.InputStreamReader@43e524c8中的START_TAG @ 1:6)
我有一个可访问.NET Web服务的Android应用。它传递一个int并接收一个int作为响应。我正在使用ksoap2。
我还向清单文件添加了权限,此外,我包括了所有jar文件。但是,我被卡住了,无法查看正在发送的SOAP请求。
我的代码是:
public class FirstAppUI extends Activity{
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL =
"http://nautilussoft.biz.whbus12.onlyfordemo.com/staging/litigation/demowebservice.asmx";
private static final String SOAP_ACTION ="http://tempuri.org/GetNumber";
private static final String METHOD_NAME = "GetNumber";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
TextView tv= (TextView)findViewById(R.id.TextView01);
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("maxbelow", "123");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet= true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try {
//Toast.makeText(getBaseContext(), "received object", Toast.LENGTH_SHORT).show();
androidHttpTransport.call(SOAP_ACTION, envelope);
Object resultsRequestSOAP = (SoapObject)envelope.getResponse();
//SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn;
//Toast.makeText(getBaseContext(), "received object", Toast.LENGTH_SHORT).show();
tv.setText("Received :" + resultsRequestSOAP.toString());
} catch (MalformedURLException e) {
e.printStackTrace();
Log.e("APP", "MalformedURLException while sending\n" + e.getMessage());
tv.setText("Malformedexception"+e);
}
catch(Exception e1)
{
e1.printStackTrace();
tv.setText("exception"+e1);
}
}
}
提前致谢。
最佳答案
在IIS中或通过IIS管理器授予对Web服务文件夹的权限。