在3次试用后未输入正确的密码时,如何使用此代码退出程序?break
不会终止程序,而是转到下一个代码块。
int cod = 2334;
while (true){
cout << "Introduce your password." << endl;
cin >> cod;
while(pass!=cod){
int counter =1;
cout << "Wrong password. You have three trials" << endl;
cin >> cod;
counter++;
if (counter == 4)
break;
}
最佳答案
break
退出最里面的块。您有2个while
,所以它将仅逃脱内部的一个。而且您的计数器永远不会达到4,因为您每次循环都将其重置为1。尝试以下方法:
int cod = 2334;
int counter = 1;
cout << "Introduce your password." << endl;
cin >> cod;
while(pass!=cod && counter < 4){
cout << "Wrong password. You have three trials" << endl;
cin >> cod;
counter++;
}