我目前正在尝试学习C ++,但是遇到了一个我不理解的编译器错误。有人可以解释一下编译器错误的含义吗?

 1 #include <thread>
 2 #include <vector>
 3 #include <iostream>
 4
 5 namespace thread_pool {
 6
 7   class worker {
 8     public:
 9       worker();
10     private:
11   };
12
13   worker::worker() { std::cout << "hello from worker\n"; }
14
15   class pool_keeper {
16     public:
17       pool_keeper(int);
18     private:
19       std::vector< std::thread > workers_;
20       int pool_size_;
21   };
22
23   pool_keeper::pool_keeper(int pool_size) {
24     int i;
25     pool_size_ = pool_size;
26     for (i=0; i<pool_size_; i++)
27       workers_.push_back(std::thread(worker()));
28   }
29 }


编译器给我这个:

In file included from /usr/lib/gcc/x86_64-pc-linux-gnu/4.6.3/include/g++-v4/thread:39:0,
            from 01.cpp:1:
/usr/lib/gcc/x86_64-pc-linux-gnu/4.6.3/include/g++-v4/functional: In member function ‘void std::_Bind_result<_Result, _Functor(_Bound_args ...)>::__call(std::tuple<_Args ...>&&, std::_Index_tuple<_Indexes ...>, typename std::_Bind_result<_Result, _Functor(_Bound_args ...)>::__enable_if_void<_Res>::type) [with _Res = void, _Args = {}, int ..._Indexes = {}, _Result = void, _Functor = thread_pool::worker, _Bound_args = {}, typename std::_Bind_result<_Result, _Functor(_Bound_args ...)>::__enable_if_void<_Res>::type = int]’:
/usr/lib/gcc/x86_64-pc-linux-gnu/4.6.3/include/g++-v4/functional:1378:24:   instantiated from ‘std::_Bind_result<_Result, _Functor(_Bound_args ...)>::result_type std::_Bind_result<_Result, _Functor(_Bound_args ...)>::operator()(_Args&& ...) [with _Args = {}, _Result = void, _Functor = thread_pool::worker, _Bound_args = {}, std::_Bind_result<_Result, _Functor(_Bound_args ...)>::result_type = void]’
/usr/lib/gcc/x86_64-pc-linux-gnu/4.6.3/include/g++-v4/thread:117:13:   instantiated from ‘void std::thread::_Impl<_Callable>::_M_run() [with _Callable = std::_Bind_result<void, thread_pool::worker()>]’
            01.cpp:29:1:   instantiated from here
/usr/lib/gcc/x86_64-pc-linux-gnu/4.6.3/include/g++-v4/functional:1287:4: error: no match for call to ‘(thread_pool::worker) ()’


我试图通过查看std :: thread的代码来理解编译器错误的含义,但是我认为有更好的方法来寻求解决方案。

最佳答案

该消息表示编译器不知道如何调用类型为thread_pool::worker的对象。 std::thread构造函数需要一个可调用的对象,即,函数或定义了operator()的对象。

解决方法是将工作从thread_pool::worker的构造函数移动到operator()()

关于c++ - C++编译器错误“对函数的调用不匹配”,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/18426167/

10-11 23:07
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