我想编写一个接受参数并使用函数的powershell脚本。
我尝试了这个:
param
(
$arg
)
Func $arg;
function Func($arg)
{
Write-Output $arg;
}
但是我得到了这个:
The term 'Func' is not recognized as the name
of a cmdlet, function, script file, or operable program.
Check the spelling of the name, or if a path was included,
verify that the path is correct and try again.
At func.ps1:6 char:5
+ Func <<<< $arg;
+ CategoryInfo : ObjectNotFound: (Func:String) [], CommandNotFoundException
+ FullyQualifiedErrorId : CommandNotFoundException
很好,我想。我将尝试以下方法:
function Func($arg)
{
Write-Output $arg;
}
param
(
$arg
)
Func $arg;
但是然后,我得到了:
The term 'param' is not recognized as the name
of a cmdlet, function, script file, or operable program.
Check the spelling of the name, or if a path was included,
verify that the path is correct and try again.
At C:\Users\akina\Documents\Work\ADDC\func.ps1:7 char:10
+ param <<<<
+ CategoryInfo : ObjectNotFound: (param:String) [], CommandNotFoundException
+ FullyQualifiedErrorId : CommandNotFoundException
我要的是可行的吗?还是我的要求不合理?
最佳答案
脚本中的param块必须是第一个非注释代码。之后,您需要先定义函数,然后再调用它,例如:
param
(
$arg
)
function Func($arg)
{
$arg
}
Func $arg
在您的示例中,不需要Write-Output,因为默认行为是将对象输出到输出流。
关于具有参数*和*功能的Powershell脚本,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/14902501/