当前肥皂故障中的故障代码有如下问题:
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/">
<env:Header/>
<env:Body>
<env:Fault xmlns:ns0="http://xmlns.telenet.be/oss/ninas/v001">
<faultcode>ns0:B-NONUNIQUE-WORKORDERID</faultcode>
<faultstring>Work order ID is not unique</faultstring>
<detail/>
</env:Fault>
</env:Body>
</env:Envelope>
但是我需要这样(没有名称空间前缀):
<faultcode>B-NONUNIQUE-WORKORDERID</faultcode>
我已经尝试过的
首先,我用spring aop拦截了肥皂故障,并实现EndpointInterceptor以获取messageContext(org.springframework.ws.context)
消息上下文具有方法“ setResponse”-它非常适合我,WebServiceMessage的API及其子类非常差,我无法以这种方式更改响应内部
尝试了其他几种方法,但情况变得更糟。
有人可以暗示要怎么做才能获取和更改故障代码吗?
或避免在错误代码中出现名称空间前缀。
最佳答案
经过数小时的调查,我发现了非常难看的解决方案。首先,我在我的xml配置文件中有一个spring拦截器:
<sws:interceptors>
<bean id="attachmentInterceptor"
class="com.net.tel.interceptors.MessageInterceptor">
</bean>
</sws:interceptors>
拦截器实现:
public class MessageInterceptor extends EndpointInterceptor {
private static final transient Logger log = LoggerFactory.getLogger(NCOssNinasAttachmentInterceptor.class);
private SoapMessageFactory soapMessageFactory;
@Autowired
private NCOssNinasAttachmentInterceptor(SoapMessageFactory soapMessageFactory) {
this.soapMessageFactory = soapMessageFactory;
}
@Override
public void afterCompletion(MessageContext messageContext, Object endpoint, Exception ex) throws Exception {
SaajSoapMessage message = (SaajSoapMessage) messageContext.getResponse();
final OutputStream s = new ByteArrayOutputStream();
message.writeTo(s);
log.info("SOAP RESPONSE: " + s.toString());
String modifiedMsg = faultCodeModifier(s.toString());
log.info("MODIFIED RESPONSE: " + modifiedMsg);
final InputStream is1 = new ByteArrayInputStream(modifiedMsg.getBytes());
SoapMessage m = soapMessageFactory.createWebServiceMessage(is1);
if (messageContext.hasResponse()) messageContext.clearResponse();
messageContext.setResponse(m);
log.info("NEW RESPONSE WAS SET");
}
如您所见,我以字符串形式获取响应并对其进行修改,从而编写了一个简单的(丑陋的)解析器:
private String faultCodeModifier(String message) {
StringBuilder sb = new StringBuilder();
String[] arr = message.split("<");
for (int i = 0; i < arr.length; i++) {
String b = arr[i];
if (arr[i].contains("faultcode") && !arr[i].contains("/")) {
String a = arr[i].split(">")[1];
String c = a.split(":")[1];
b = arr[i].split(">")[0] + ">" + c;
}
if (!"".equals(arr[i])) sb.append("<" + b);
}
return sb.toString();
}
最后,我将创建新的响应并将其插入消息上下文中。通过我不满意解决了所有问题。如果有人有更好的解决方案,请分享。