java - 如何遍历包含对象的LinkedList-Java

我如何遍历我添加了对象的LinkedList？

private LinkedList sensors = new LinkedList();
enter code here

//Constructor for my class is taking three arguments
public Sensor(int ID, String Name, String comments) {
    this.ID = ID;
    this.NAME = Name;
    this.COMMENTS = comments;
}

//Then I query the database to get the values of the variables to create a new Object
ID = Integer.parseInt(dbResult.getString("sensorID") );
        NAME = dbResult.getString("sensorName");
        COMMENTS = dbResult.getString("sensorcomments");

        //create a new sensor object
        Sensor newSensor = new Sensor(ID, NAME, COMMENTS);

        //add the sensor to the list
        addSensor(newSensor);

`
我遇到的问题是我可以将传感器对象添加到“链接列表”，但是当我尝试遍历它时，得到的结果是引用而不是对象或其值。

//display the results of the Linked List
System.out.println(Arrays.toString(sensors.toArray()));

我得到的输出是
[Sensor @ 4d405ef7，Sensor @ 6193b845，Sensor @ 2e817b38，Sensor @ c4437c4，Sensor @ 433c675d，Sensor @ 3f91beef]

谢谢

最佳答案

在toString()类中需要一个Sensor方法。

@Override
public String toString() {
    return "id: "+ID+"; name: "+NAME+"; comments: "+ COMMENTS;
}

Arrays.toString(Object[] a)将调用每个Sensor对象的toString()方法。

这是带有建议的变量名称更改的Sensor类的更完整示例：

class Sensor {

    private int id;
    private String name;
    private String comments;

    public Sensor(int id, String name, String comments) {
        this.id = id;
        this.name = name;
        this.comments = comments;
    }

    @Override
    public String toString() {
        //You can change how to the string is built in order to achieve your desired output.
        return "id: "+ID+"; name: "+name+"; comments: "+ comment;
    }

}

关于java - 如何遍历包含对象的LinkedList-Java，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/28994299/