我在项目中使用Konva JS。我在可拖动的按钮单击上添加了形状。单击形状时,我需要获取形状的X和Y位置。 getX
和getY
函数返回原始的X和Y。拖动后如何更新X和Y。
下面的示例代码。
var stage = new Konva.Stage({
container: 'canvas', // id of container <div>
width: 500,
height:300
});
jQuery("#add-shape").click(function(){
addShape();
});
var addShape = function(){
console.log("add shape");
var layer = new Konva.Layer();
var parentContainer = new Konva.Rect({
x: stage.getWidth() / 2,
y: stage.getHeight() / 2,
width: 200,
height: 60,
cornerRadius: 10,
fill: '#ccc'
});
var smallCircle = new Konva.Circle({
x: stage.getWidth() / 2 + 200,
y: stage.getHeight() / 2 + 30,
radius: 15,
fill: "#F2784B",
stroke: "white",
strokeWidth: 2
});
smallCircle.on('click', function() {
console.log(this.getX(),this.getY());
addArrow(this.getX(),this.getY());
//get current X and Y here instead of origina X and Y
});
layer.add(parentContainer);
layer.add(smallCircle);
layer.draggable('true');
stage.add(layer);
}
var addArrow = function(arrowX,arrowY){
var connectorLayer = new Konva.Layer();
var connector = new Konva.Arrow({
points: [arrowX,arrowY,arrowX+10,arrowY],
pointerLength: 4,
pointerWidth: 4,
fill: 'black',
stroke: 'black',
strokeWidth: 2
});
connectorLayer.add(connector);
stage.add(connectorLayer);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdn.rawgit.com/konvajs/konva/1.0.2/konva.min.js"></script>
<button id="add-shape">
Add shape
</button>
<div id="canvas">
</div>
最佳答案
如果需要获取鼠标位置,可以使用:
smallCircle.on('click', function() {
console.log(stage.getPointerPosition());
});
关于javascript - 拖入Konva JS后获得形状的X和Y,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/38409306/