我知道这些注释@JsonInclude(JsonInclude.Include.NON_NULL)和@JsonInclude(JsonInclude.Include.EMPTY),但在我的情况下不起作用。
我的情况是:
我有一些类(实体(SomeClass))和其他实体(SomeObject)
@Data
public class SomeClass {
private String fieldOne;
@JsonInclude(JsonInclude.Include.NON_NULL)
private String fieldTwo;
@JsonInclude(JsonInclude.Include.NON_NULL)
private SomeObject someObject;
}
实体-SomeObject
@Data
public class SomeObject {
@JsonInclude(JsonInclude.Include.NON_NULL)
private String name;
}
主班
public class Main {
public static void main(String[] args) throws JsonProcessingException {
SomeClass someClass = new SomeClass();
someClass.setFieldOne("some data");
SomeObject someObject = new SomeObject();
someObject.setName(null);
someClass.setSomeObject(someObject);
ObjectMapper objectMapper = new ObjectMapper();
String someClassDeserialized = objectMapper.writeValueAsString(someClass);
System.out.println(someClassDeserialized);
}
}
输出量
{"fieldOne":"some data","someObject":{}}
最终输出应为不包含空字段或空字段的对象(SomeObject):
{"fieldOne":"some data"}
最佳答案
我认为只能在此处应用自定义逻辑。您需要使用@JsonInclude(value = JsonInclude.Include.CUSTOM, valueFilter = YourFilter.class)
并创建自定义YourFilter
类。您可以使用boolean方法创建基本接口,并在所有需要根据该类中所有/所需字段的空性将其过滤掉的类中重写它。
或者,您可以在此方法中解析@JsonInclude(JsonInclude.Include.NON_NULL)
批注,以获取所有字段,您需要检查这些字段是否为空。
https://www.logicbig.com/tutorials/misc/jackson/json-include-customized.html