javascript - 如何从AJV错误中获取“标题”？

我有一个看起来像这样的JSON模式：

{
  "required": [
    "instructions"
  ],
  "properties": {
    "instructions": {
      "title": "Instructions",
      "minItems": 3,
      "type": "array",
      "items": {
        "required": [
          "typeId",
          "teamId",
          "disciplineId"
        ],
        "properties": {
          "typeId": {
            "minimum": 1,
            "title": "Appointment Type",
            "type": "integer"
          },
          "teamId": {
            "minimum": 1,
            "title": "Team",
            "type": "integer"
          },
          "disciplineId": {
            "minimum": 1,
            "title": "Discipline",
            "type": "integer"
          },
          "prefClinicianId": {
            "title": "Pref. Clinician",
            "anyOf": [
              {
                "type": "null"
              },
              {
                "minimum": 1,
                "type": "integer"
              }
            ]
          },
          "prefTime": {
            "title": "Pref. Time",
            "anyOf": [
              {
                "type": "null"
              },
              {
                "type": "integer"
              }
            ]
          },
          "childRequired": {
            "title": "Child Req'd",
            "type": "boolean"
          }
        },
        "type": "object"
      }
    }
  },
  "type": "object"
}

如您所见，我已经将title添加到所有属性中。但是，我返回的错误对象如下所示：

[
  {
    "keyword": "minItems",
    "dataPath": ".instructions",
    "schemaPath": "#/properties/instructions/minItems",
    "params": {
      "limit": 3
    },
    "message": "should NOT have less than 3 items"
  },
  {
    "keyword": "type",
    "dataPath": ".instructions[0].typeId",
    "schemaPath": "#/properties/instructions/items/properties/typeId/type",
    "params": {
      "type": "integer"
    },
    "message": "should be integer"
  },
  {
    "keyword": "type",
    "dataPath": ".instructions[0].teamId",
    "schemaPath": "#/properties/instructions/items/properties/teamId/type",
    "params": {
      "type": "integer"
    },
    "message": "should be integer"
  },
  {
    "keyword": "type",
    "dataPath": ".instructions[0].disciplineId",
    "schemaPath": "#/properties/instructions/items/properties/disciplineId/type",
    "params": {
      "type": "integer"
    },
    "message": "should be integer"
  }
]

如您所见，title不在其中。如何获得带有错误的标题？

请注意，此问题特定于AJV。

最佳答案

创建AJV对象时，请设置verbose option to true。

这将在原始模式的ajv错误中添加parentSchema属性。它还将添加一个schema属性，该属性包含导致验证失败的特定架构属性。

这是一个例子：

var ajv = new Ajv({
  $data: true,
  verbose: true
});

let schema = {
  title: 'object title',
  type: 'object',
  properties: {
    str: {
      title: "A string property",
      type: "string"
    }
  }
};

let data = {
  str: 3
};

ajv.validate(schema, data)

console.log('ERRORS: ', this.ajv.errors)

<script src="https://cdnjs.cloudflare.com/ajax/libs/ajv/5.3.0/ajv.bundle.js"></script>

关于javascript - 如何从AJV错误中获取“标题”？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/47403680/