我正在解析一个xml文件,其中包含带有如下文本的节点:
<?xml version="1.0" encoding="iso-8859-1"?>
<country>
<name> France </name>
<city> Paris </city>
<region>
<name> Nord-Pas De Calais </name>
<population> 3996 </population>
<city> Lille </city>
</region>
<region>
<name> Valle du Rhone </name>
<city> Lyon </city>
<city> Valence </city>
</region>
</country>
我想要得到的是这样的值:
country -> name.city.region*
region -> name.(population|epsilon).city*
name -> epsilon
city -> epsilon
population -> epsilon
我不知道这样做的方法
最佳答案
我添加了一个示例程序。请继续以相同的方式阅读。
public class TextXML {
public static void main(String[] args) {
try {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(new File("text.xml"));
// list of country elements
NodeList listOfCountry = doc.getElementsByTagName("country");
for (int s = 0; s < listOfCountry.getLength(); s++) {
Node countyNode = listOfCountry.item(s);
if (countyNode.getNodeType() == Node.ELEMENT_NODE) {
Element countyElement = (Element) countyNode;
NodeList nameList = countyElement.getElementsByTagName("name");
// we have only one name. Element Tag
Element nameElement = (Element) nameList.item(0);
System.out.println("Name : " + nameElement.getTextContent());
NodeList cityList = countyElement.getElementsByTagName("city");
// we have only one name. Element Tag
Element cityElement = (Element) cityList.item(0);
System.out.println("City : " + cityElement.getTextContent());
NodeList regionList = countyElement.getElementsByTagName("region");
// we have only one name. Element Tag
Element regionElement = (Element) regionList.item(0);
System.out.println("Region : " + regionElement.getTextContent());
//continue further same way.
}
}
} catch (SAXParseException err) {
err.printStackTrace();
} catch (SAXException e) {
Exception x = e.getException();
((x == null) ? e : x).printStackTrace();
} catch (Throwable t) {
t.printStackTrace();
}
}
}
关于java - 使用从XML文件提取的数据创建正则表达式,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/10395825/