ruby-on-rails - 找不到 'id' = all，搜索表单的 list

所以这很奇怪。
我遵循了这个railscast http://railscasts.com/episodes/37-simple-search-form
当我实现所有内容后，它看起来像这样

index.html.erb

<%= form_tag findjobs_path, :method => 'get' do %>
      <p>
      <%= text_field_tag :search %>
      <%= submit_tag "search" %>
       </p>
<% end %>

listings_controller.rb

    def index
    @listings = Listing.all
    @listings = Listing.paginate(:page => params[:page], :per_page => 10)
    @user = User.find_by_name(params[:name])
    @listing = Listing.find_by_id(params[:id])
    @categories = Category.all
    @listings = Listing.search(params[:search])
    end
end

listing.rb

def self.search(search)
  if search
    find(:all, :conditions => ['name LIKE ?', "%#{search}%"])
  else
    find(:all)
  end
end

我收到以下错误:找不到带有'id'= all的 list
我知道find方法会立即查找ID。
但是，我不知道如何设置它，以便它可以搜索我所有的列表。
find_by_all当然不起作用。

我希望任何人都可以帮助

太谢谢你了

最佳答案

如何修改listing.rb搜索方法？

def self.search(search)
  if search
    self.where("name like ?", "%#{search}%")
  else
    self.all
  end
end

加..

listings_controller.rb

def index
  @listings = Listing.all
  # Patching all Listing

  @listing = Listing.where(id: params[:id]) if params[:id].present?
  # Find By Id (For pagination, the 'where' statement result is Listing ActiveRecord::Relationship )
  @listings = @listings.search(params[:search]) if params[:search].present?
  # Search using Keyword
  @listings = @listings.paginate(:page => params[:page], :per_page => 10)
  # Pagination
  @user = User.find_by_name(params[:name]) if params[:name].present?
  # Find User using name column
  @categories = Category.all

end

关于ruby-on-rails - 找不到 'id' = all，搜索表单的 list ，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/25777318/