我将如何使用类似的 IN 表?这样我就可以在其中使用 % 了吗?我的意思是:
SELECT fields
FROM table
WHERE age = "50"
AND name IN ("tim", "bob", "nancy", "john");
我已经尝试过:
SELECT fields
FROM table
WHERE age = "50"
AND name LIKE ("2010-09-17%", "2010-09-16%")
但它给出了错误“操作数应该包含 1 列”
最佳答案
您可以使用许多 LIKE 表达式:
SELECT fields
FROM table
WHERE age = "50"
AND (
name LIKE "2010-09-17%"
OR name LIKE "2010-09-16%"
);
或者您可以使用正则表达式:
SELECT fields
FROM table
WHERE age = "50"
AND name REGEXP "2010-09-17.*|2010-09-16.*";
或者,巧妙地
SELECT fields
FROM table
WHERE age = "50"
AND name REGEXP "2010-09-1(6|7).*";
关于sql - MySQL IN 和 LIKE,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/3732246/