大家好,我正在尝试将文本设置为标签。代码如下:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
newsDataCell *cell = (newsDataCell*)[tableView dequeueReusableCellWithIdentifier:@"newsData"];
if (cell == nil)
{
cell = [[newsDataCell alloc]initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"newsData"];
}
NSDictionary* currentrow =[self.Items objectAtIndex:indexPath.item];
NSLog(@"currentrow:%@",currentrow);
//UIImageView *image = (UIImageView*)[cell viewWithTag:0];
UILabel *txtData = (UILabel*)[cell viewWithTag:1];
NSString *testo = [currentrow objectForKey:@"Date"];
[txtData setText:testo];
UILabel *txtTitolo = (UILabel*)[cell viewWithTag:2];
txtTitolo.text =[currentrow valueForKey:@"Title"];
UILabel *txtDescrizione = (UILabel*)[cell viewWithTag:3];
txtDescrizione.text = [currentrow valueForKey:@"Descr"];
return cell;
}
我检查了一下,currentrow实际上包含了该对象。
这是我从Xcode得到的错误:
2013-09-11 16:04:36.468 ApplicationName [2409:c07] *由于未捕获的异常'NSInvalidArgumentException'而终止应用程序,原因:'-[__ NSArrayM objectForKey:]:无法识别的选择器已发送至实例0x7172f80'
* 首先抛出调用堆栈:
(0x1333012 0x1158e7e 0x13be4bd 0x1322bbc 0x132294e 0xc5f4 0x1578fb 0x1579cf 0x1401bb 0x150b4b 0xed2dd 0x116c6b0 0x265bfc0 0x265033c 0x2650150 0x25ce0bc 0x25cf227 0x25cf8e2 0x12fbafe 0x12fba3d 0x12d97c2 0x12d8f44 0x12d8e1b 0x22757e3 0x2275668 0x9cffc 0x2c2d 0x2b55)
libc ++ abi.dylib:终止调用引发异常
我使用valueForKey遇到相同的错误:
txtTitolo.text =[currentrow valueForKey:@"Title"];
这里是:
2013-09-11 16:09:34.478 ApplicationName [2409:c07] *由于未捕获的异常'NSInvalidArgumentException'而终止应用程序,原因:'-[__ NSArrayM valueForKey:]:无法识别的选择器已发送至实例0x7172f80'
* 首先抛出调用堆栈:
(0x1333012 0x1158e7e 0x13be4bd 0x1322bbc 0x132294e 0xc5f4 0x1578fb 0x1579cf 0x1401bb 0x150b4b 0xed2dd 0x116c6b0 0x265bfc0 0x265033c 0x2650150 0x25ce0bc 0x25cf227 0x25cf8e2 0x12fbafe 0x12fba3d 0x12d97c2 0x12d8f44 0x12d8e1b 0x22757e3 0x2275668 0x9cffc 0x2c2d 0x2b55)
libc ++ abi.dylib:终止调用引发异常
怎么了谢谢!!
最佳答案
看起来currentrow
不是NSDictionary
(您假设)。这是一个NSArray
。
NSDictionary* currentrow =[self.Items objectAtIndex:indexPath.item];
// Not a dictionary, it is an array.
这就是为什么您会发生此崩溃。如果这是已解析的JSON响应,请检查JSON的结构。
希望有帮助!