我正在尝试使用xmpp的消息事件接口。据我所知,您可以将您发送的邮件标记为“已请求传递通知”,收件人有责任向您发送此通知。有人成功地实现了这一点吗?有人能寄给我一些样本代码吗?我的代码不起作用。从不调用侦听器(MessageEventNotificationListener、MessageEventrequestListener)的回调:

@Override
public void onCreate( Bundle savedInstanceState )
{
    super.onCreate( savedInstanceState );
    setContentView( R.layout.chat );

    PacketFilter filter = new MessageTypeFilter(Message.Type.chat);
    VajasKifli.connection.addPacketListener( this, filter );

    tv = ( TextView ) findViewById( R.id.textView1 );
    tvState = ( TextView ) findViewById( R.id.textView2 );
    et = ( EditText ) findViewById( R.id.editText1 );
    et.addTextChangedListener( this );

    mem = new MessageEventManager( VajasKifli.connection );
    mem.addMessageEventNotificationListener( this );
    mem.addMessageEventRequestListener( this );

    sdm = new ServiceDiscoveryManager( VajasKifli.connection );
    VajasKifli.log( "sdm: " + sdm );

    stateManager = ChatStateManager.getInstance( VajasKifli.connection );

    recipient = getIntent().getStringExtra( "recipient" );
    chat = VajasKifli.connection.getChatManager().createChat( recipient, "chat-" + recipient, this );
    VajasKifli.log( "chat created: " + chat );

    VajasKifli.connection.getChatManager().addChatListener( this );

    sv = ( ScrollView ) findViewById( R.id.scrollView1 );

    handler = new ChatHandler();
}

public void onClickSend( View view )
{
    String text = et.getText().toString();
    if( text.length() > 0 )
    {
        VajasKifli.log( "sending text [" + text + "] to [" + recipient + "]" );

        try
        {
            Message message = new Message();
            message.setBody( text );
            MessageEventManager.addNotificationsRequests( message, false, true, false, false );
            chat.sendMessage( message );

            stateManager.setCurrentState( ChatState.active, chat );
            lastState = ChatState.active;
            tv.append( "\n" + VajasKifli.connection.getUser().replaceFirst( "@.*", "" ) + ": " + text );
            sv.fullScroll( ScrollView.FOCUS_DOWN );
        }
        catch( XMPPException e )
        {
            VajasKifli.logError( e.toString() );
        }

        //showToast( "sent: " + text );
    }
}

最佳答案

您应该通过wireshark或smack debug选项获得xmpp连接的数据包跟踪,以确保传递通知确实是由连接的另一端发送的。如果没有,这将解释为什么没有调用侦听器。
smack中的消息事件是通过现在已经过时的XEP-22完成的。很有可能对方没有实施这一过时的机制。

关于android - Android Smack MessageEventListener,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7241444/

10-10 17:09