c++ - 'element' 的初始化被 'case' 标签跳过

这个问题在这里已经有了答案:





Why can't variables be declared in a switch statement?

(23 个回答)


3年前关闭。




我不明白为什么我收到错误:



有人可以向我解释一下吗？

void LinkedList::process_example(int choice) {
    switch(choice) {
    case 1:
        cout << endl << endl << "Current S = ";
        this->printSet();

        cout << "Enter an element :";
        char* element = "lol";

        //cin>>element;
        cin.clear();
        cin.ignore(200, '\n');

        this->Addelementfromback(element); //error is here
        cout << endl << endl << "Current S = ";

        this->printSet();
        break;

    case 2:
        this->check_element();
        break;

    case 3:
        cout << endl << endl;
        cout << "Current Set S = ";
        this->printSet();

        cout << endl << "S has ";
        int count = this ->check_cardinality();
        cout << count << " elements";
        break;
    }
}

最佳答案

尝试用 case 包裹 {} ，并将所有语句放入 {} 。

case 1:
{
   cout << endl << endl << "Current S = ";
   this->printSet();
   // and other mess
}
break;

你应该把所有这些语句都放在函数中，保持 case 语句清晰。例如，编写这种样式:

case 1:
   initializeElement();
   break;
case 2:
   doSomethingElse();
   break;

见 link

关于c++ - 'element' 的初始化被 'case' 标签跳过，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/14669457/