程序将要求用户输入两个复数的实部和虚部。程序应该输出复数的和、差、积、商和绝对值,格式为小数点后两位。
一切正常,除了代码中的abs值部分,每当我运行它时,都会得到一些奇怪的数字,abs值应该在哪里,例如-1.644534634或-1.4363465。
所以当我在看的时候,我注意到我忘了在顶部添加#include <math.h>
,但是,当我这样做的时候,所有的事情都变得一团糟,我得到了61个关于如何操作的错误。real和.img不是complex的一部分。
如果可能的话,你能看看我的abs值方法,看看我写的是否正确,谢谢。
#include <stdio.h>
//#include <math.h>
struct complex
{
float real;
float img;
};
struct complex add_complex(struct complex c1, struct complex c2);
struct complex subtract_complex(struct complex c1, struct complex c2);
struct complex multiply_complex(struct complex c1, struct complex c2);
struct complex divide_complex(struct complex c1, struct complex c2);
double abs_complex(struct complex c);
void main()
{
struct complex c, c1, c2, tempa, temps, tempm, tempd;
double abs1, abs2;
printf("Enter the real part of the 1st complex number:\n");
scanf("%f", &c1.real);
printf("Enter the imaginary part of the 1st complex number:\n");
scanf("%f", &c1.img);
printf("Enter the real part of the 2nd complex number:\n");
scanf("%f", &c2.real);
printf("Enter the imaginary part of the 2nd complex number:\n");
scanf("%f", &c2.img);
tempa = add_complex(c1, c2);
temps = subtract_complex(c1, c2);
tempm = multiply_complex(c1, c2);
tempd = divide_complex(c1, c2);
abs1 = abs_complex(c1);
abs2 = abs_complex(c2);
printf("\n");
if (tempa.real == 0)
printf("(%.2f + %.2fi) + (%.2f + %.2fi) = (%.2fi)\n", c1.real, c1.img, c2.real, c2.img, tempa.img);
else if (tempa.img == 0)
printf("(%.2f + %.2fi) + (%.2f + %.2fi) = (%.2f)\n", c1.real, c1.img, c2.real, c2.img, tempa.real);
else
printf("(%.2f + %.2fi) + (%.2f + %.2fi) = (%.2f + %.2fi)\n", c1.real, c1.img, c2.real, c2.img, tempa.real, tempa.img);
if (temps.real == 0)
printf("(%.2f + %.2fi) - (%.2f + %.2fi) = (%.2fi)\n", c1.real, c1.img, c2.real, c2.img, temps.img);
else if (temps.img == 0)
printf("(%.2f + %.2fi) - (%.2f + %.2fi) = (%.2f)\n", c1.real, c1.img, c2.real, c2.img, temps.real);
else
printf("(%.2f + %.2fi) - (%.2f + %.2fi) = (%.2f + %.2fi)\n", c1.real, c1.img, c2.real, c2.img, temps.real, temps.img);
if (tempm.real == 0)
printf("(%.2f + %.2fi) * (%.2f + %.2fi) = (%.2fi)\n", c1.real, c1.img, c2.real, c2.img, tempm.img);
else if (tempm.img == 0)
printf("(%.2f + %.2fi) * (%.2f + %.2fi) = (%.2f)\n", c1.real, c1.img, c2.real, c2.img, tempm.real);
else
printf("(%.2f + %.2fi) * (%.2f + %.2fi) = (%.2f + %.2fi)\n", c1.real, c1.img, c2.real, c2.img, tempm.real, tempm.img);
if (tempd.real == 0)
printf("(%.2f + %.2fi) / (%.2f + %.2fi) = (%.2fi)\n", c1.real, c1.img, c2.real, c2.img, tempd.img);
else if (tempd.img == 0)
printf("(%.2f + %.2fi) / (%.2f + %.2fi) = (%.2f)\n", c1.real, c1.img, c2.real, c2.img, tempd.real);
else
printf("(%.2f + %.2fi) / (%.2f + %.2fi) = (%.2f + %.2fi)\n", c1.real, c1.img, c2.real, c2.img, tempd.real, tempd.img);
printf("|(%.2f + %.2fi)| = (%.2d)\n", c1.real, c1.img, abs1);
printf("|(%.2f + %.2fi)| = (%.2d)\n", c2.real, c2.img, abs2);
printf("\n");
}
struct complex add_complex(struct complex c1, struct complex c2)
{
struct complex tempa;
tempa.real = c1.real + c2.real;
tempa.img = c1.img + c2.img;
return(tempa);
}
struct complex subtract_complex(struct complex c1, struct complex c2)
{
struct complex temps;
temps.real = c1.real - c2.real;
temps.img = c1.img - c2.img;
return(temps);
}
struct complex multiply_complex(struct complex c1, struct complex c2)
{
struct complex tempm;
tempm.real = c1.real*c2.real - c1.img*c2.img;
tempm.img = c1.real*c2.img + c1.img*c2.real;
return(tempm);
}
struct complex divide_complex(struct complex c1, struct complex c2)
{
struct complex tempd, temp1, temp2;
temp1.real = c1.real*c2.real + c1.img*c2.img;
temp2.real = c2.real*c2.real + c2.img*c2.img;
temp1.img = c1.img*c2.real - c1.real*c2.img;
temp2.img = c2.real*c2.real + c2.img*c2.img;
tempd.real = temp1.real / temp2.real;
tempd.img = temp1.img / temp2.img;
return(tempd);
}
double abs_complex(struct complex c)
{
double temp1, temp2;
double abs;
temp1 = c.real*c.real;
temp2 = c.img*c.img;
abs = sqrt(temp1 + temp2);
return(abs);
}
最佳答案
第一部分:math.h
可能包含了创建此宏的complex.h
:
#define complex _Complex
我建议重命名您的复杂类型,或者使用here中描述的内置类型。
您也可以在
#undef complex
之后进行#include <main.h>
操作,但对于可能无法持续的大型程序。第2部分:
打印绝对值时使用了错误的格式说明符。以下是clang发出的警告,这些警告清楚地解释了问题并提供了解决方案:
foo.c:68:60: warning: format specifies type 'int' but the argument has type 'double' [-Wformat]
printf("|(%.2f + %.2fi)| = (%.2d)\n", c1.real, c1.img, abs1);
~~~~ ^~~~
%.2f
foo.c:69:60: warning: format specifies type 'int' but the argument has type 'double' [-Wformat]
printf("|(%.2f + %.2fi)| = (%.2d)\n", c2.real, c2.img, abs2);
~~~~ ^~~~
%.2f
关于c - 删除“#include <math.h>”前面的注释会破坏我的代码,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/26127112/