我有一个问题,我有这样的SOAP请求信封:

<soapenv:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:str="http://string.soap.webservices.invent.telkom.co.id"><soapenv:Header/>
<soapenv:Body>
    <str:PhyStatus soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
        <ip xsi:type="xsd:string">172.20.20.123</ip>
        <slot xsi:type="xsd:string">4</slot>
        <port xsi:type="xsd:string">33</port>
    </str:PhyStatus>
</soapenv:Body>
</soapenv:Envelope>


我有WSDL,其服务具有不同的参数,但与输入的数字相同。
在Java中,如何将SOAP请求发送到此WSDL?

对于您的信息,这是我想要的输出(SOAP响应):

<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://string.soap.webservices.invent.telkom.co.id" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<SOAP-ENV:Body>
    <ns1:PhyStatusResponse>
        <PhyStatusReturn xsi:type="SOAP-ENC:Struct">
            <AdminStatus xsi:type="xsd:string">Active</AdminStatus>
            <LinkStatus xsi:type="xsd:string">Activating</LinkStatus>
            <LineProfile xsi:type="xsd:string">ADSL LINE PROFILE 10</LineProfile>
        </PhyStatusReturn>
    </ns1:PhyStatusResponse>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>

最佳答案

您可以使用任何http客户端将您的soap消息发布到该服务,该服务是url删除“?wsdl”

07-24 09:45
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