我有一个创建行的循环，其中每一行都有另一个循环来创建6个JRadioButton。
每行只能选择一个JRadioButton（应该如此），但是我发现很难使用动作侦听器检查是否已从每一行中选择了正确的JRadioButton，然后将空的JLabel更改为显示“正确的” ”，但是我认为，一旦我完成了第一部分，这将很简单。
这是我正在使用的相关代码：
//loop for making flow layout for each line of random letters
//counter for having number of the row next to each row in order of selection
int counter = x;
for(int i = 0; i < x; i++)
{
//new jpanel created for every row needed for the word
JPanel jpLine = new JPanel(new FlowLayout());
//new jlabel made with counter number for each row
JLabel count = new JLabel(Integer.toString(counter));
jpLine.add(count);
counter--;
//random number from 0-5 generated for each row
Random number = new Random();
int low = 0;
int high = 5;
int ranNumber = number.nextInt((high - low) + low);
//buttongroup outside loop so only one button can be pressed for each row
ButtonGroup bg = new ButtonGroup();
//get selected button's index in any group with bg.getSelection().getActionCommand()
final int row = i;
final ButtonGroup btnG = bg;
ActionListener listener = new ActionListener()
{
public void actionPerformed(ActionEvent e)
{
System.out.println("row " + row);
System.out.println("btn " + btnG.getSelection().getActionCommand());
}
};
//loop for making the number of letters in each row - always going to be 6 letters to choose from in each row
for(int j = 0; j < 5; j++)
{
//if the random number generated for each row equals the loop
//then new radiobutton will be created for the ith letter of the reversed
//answer, starting from charAt 0 and going to the last character
if(ranNumber == j)
{
JRadioButton answerLetter = new JRadioButton("<html><font color = 'white'>" + answerForGrid.charAt(i) + "</font></html>");
bg.add(answerLetter);
answerLetter.setBackground(Color.decode("#566771"));
answerLetter.setOpaque(true);
jpLine.add(answerLetter);
//use setActionCommand("" + j) on each button to associate each button with its index
answerLetter.setActionCommand("" + j);
answerLetter.addActionListener(listener);
}
//ranLetter is generated randomly from the alphabet string, so random letters are
//created for each jradiobutton
final String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
final int N = alphabet.length();
Random letter = new Random();
char ranLetter;
while(true)
{
ranLetter = alphabet.charAt(letter.nextInt(N));
break;
}
JRadioButton k = new JRadioButton("<html><font color = 'white'>" + ranLetter + "</font></html>");
bg.add(k);
k.setBackground(Color.decode("#566771"));
k.setOpaque(true);
jpLine.add(k);
}
//add each row of letters (jpLine) to this loops jpanel
jpCenterCenter.add(jpLine);
}
另外，我要检查的正确JRadioButton是在if（ranNumber == j）部分中创建的。
抱歉，如果我继续这样做，但是我发现这很难解释，因此希望有人能够提供帮助！
最佳答案
您可以在每个按钮上使用setActionCommand("" + j)将每个按钮与其索引相关联，然后使用bg.getSelection().getActionCommand()获取任何组中所选按钮的索引。然后，您可以将一个ActionListener分配给一个组中的所有按钮，并确保操作侦听器知道它附加到的行。
// in your "i" loop
final int row = i; // must be final to be used inside the anonymous class
final ButtonGroup btnG = bg;
final String answerAction = "" + ranNumber; // hard to tell if this is what you mean
ActionListener listener = new ActionListener() {
public void actionPerformed(ActionEvent e) {
System.out.println("row " + row);
String selectedAction = btnG.getSelection().getActionCommand();
System.out.println("btn " + selection);
boolean isCorrectForThisRow = (answerAction == selectedAction);
System.out.println("is correct: " + isCorrectForThisRow);
}
};
// in your "j" loop, with either the answerLetter or k buttons
// as required
k.setActionCommand("" + j);
k.addActionListener(listener);
就目前而言，示例中有很多内容并没有多大意义，因此很难提出更多建议（例如，
while(true)循环在第一次迭代时就中断了）。但是，正是使用setActionCommand（oracle tutorial here）来找出在按钮组中选中了哪个按钮。关于java - 检查是否已在循环中创建了哪些jRadioButton，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/28266013/