我需要有关片段内Android集成的帮助,当代码在Activity中实现时,它可以很好地工作,但就我而言,我需要在片段中实现它。

我正在尝试从Fragment调用dropin ui,但无法这样做。

我遵循的步骤:-
1)我使用get_braintree_token(rootview.getContext())获取了Braintree令牌。

2)获得令牌后,我将其传递给onBraintreeSubmit(braintreeToken,viewb)
3)当它到达onBraintreeSubmit函数中的startActivityForResult()时,BrainTree UI不会膨胀,它直接移动到具有结果代码1和一些随机请求代码的onActivityResult()。
我已经在下面编写了我的函数。

public View onCreateView(LayoutInflater inflater, ViewGroup   container,Bundle savedInstanceState) {

rootview = inflater.inflate(R.layout.fragment_map, container, false);
get_braintree_token(rootview.getContext());
return rootview;
  }
public void get_braintree_token(final Context viewb)
{

StringRequest stringRequest = new StringRequest(Request.Method.GET, "My    server URL",    new Response.Listener<String>() {
                    @Override
                    public void onResponse(String     response) {

                    braintreeToken = response.toString();
                    Log.e("Braintreetoken","token is:"+braintreeToken);

                    onBraintreeSubmit(braintreeToken, viewb);

                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            braintreeToken = null;
        }
    });
// Add the request to the RequestQueue.
    requestQueue.add(stringRequest);

}


public void onBraintreeSubmit(String token, Context c) {
    Log.e("tokenreceived",token);
    DropInRequest dropInRequest = new  DropInRequest();

    dropInRequest.clientToken(token);
    Intent drop = dropInRequest.getIntent(c);
    startActivityForResult(drop, BRAINTREE_REQUEST_CODE);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == BRAINTREE_REQUEST_CODE) {
        if (resultCode == 1) {
            DropInResult result = data.getParcelableExtra(DropInResult.EXTRA_DROP_IN_RESULT);
            // use the result to update your UI and send the payment method nonce to your server
        } else if (resultCode == Activity.RESULT_CANCELED) {
            // the user canceled
        } else {
            // handle errors here, an exception may be available in
            Exception error = (Exception) data.getSerializableExtra(DropInActivity.EXTRA_ERROR);
        }
    }
}

最佳答案

传递令牌值,此处传递的是Json响应,它正在创建问题,因此从响应中提取令牌并将其传递给braintree方法,而不是传递json响应。

09-10 06:58
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